is the solution correct?

for numbres 50 70 13 14 7 add all find sum for even find how many odd use one loop

sume=0;

sum=0;

for x=1:5

z = input ('z=')

sum=sum+z;

if mod(z,2)==03

sume=sume+z;

end

if mod(z,2)~=0

count0= count+1;

end

end

is the solution correct?

[Torsten]

is the solution correct?

Easy to check by yourself:

Z=[50 70 13 14 7];
sume=0;
sum=0;
for x=1:5 
    z = Z(x);
    sum=sum+z;
    if mod(z,2)==03
        sume=sume+z;
    end
    if mod(z,2)~=0
        count0= count+1;
        
    end
end

Error using count
Not enough input arguments.

Answer 1

[Diwakar Diwakar]

numbers = [50, 70, 13, 14, 7];
sum_all = 0;
sum_even = 0;
odd_count = 0;

for i = 1:length(numbers)
    num = numbers(i);
    sum_all = sum_all + num;  % Adding to the sum of all numbers
    
    if mod(num, 2) == 0
        sum_even = sum_even + num;  % Adding to the sum of even numbers
    else
        odd_count = odd_count + 1;  % Counting odd numbers
    end
end

fprintf('Sum of all numbers: %d\n', sum_all);

Sum of all numbers: 154

fprintf('Sum of even numbers: %d\n', sum_even);

Sum of even numbers: 134

fprintf('Count of odd numbers: %d\n', odd_count);

Count of odd numbers: 2

output:

Sum of all numbers: 154
Sum of even numbers: 134
Count of odd numbers: 3

[Walter Roberson]

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