Seventh order differential equation

조회 수: 4 (최근 30일)
Francesco Marchione
Francesco Marchione 2023년 4월 13일
편집: Torsten 2023년 4월 21일
Hello,
I would like to solve this system of differential equations in Matlab (and in the end I would like to plot tau and sigma for -l and +l x values):
with these BCs:
where P, h_i, G_i, h_i are numbers (which I would like to define in the code).
Here I started with this:
% y''''''' - a*y'''''' + b*y''' - c*y' = 0
syms s x y(x) Y
Dy = diff(y);
D2y = diff(y,2);
D3y = diff(y,3);
D4y = diff(y,4);
D5y = diff(y,5);
D6y = diff(y,6);
D7y = diff(y,7);
a==10
b==60
c==40
Eqn = D7y - a*D5y + b*D3y -c*Dy == 0;

채택된 답변

Torsten
Torsten 2023년 4월 14일
편집: Torsten 2023년 4월 15일
% Set model parameters
l = 1;
P = 1;
Ga = 1;
Eatilde = 1;
ha = 1;
E1tilde = 1;
h1 = 1;
E2tilde = 1;
h2 = 1;
xmesh = linspace(-l,l,100);
solinit = bvpinit(xmesh, [1 1 1 1 1 1 1 0 0 0]);
sol = bvp4c(@(x,y)bvpfcn(x,y,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2), @(ya,yb)bcfcn(ya,yb,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2),solinit);
x = sol.x;
tau = sol.y(1,:);
sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*sol.y(2,:)- ha/Ga*sol.y(4,:))/(6/(E1tilde*h1^2));
figure(1)
plot(x,tau)
figure(2)
plot(x,sigma)
function dydx = bvpfcn(x,y,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2)
sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*y(2) - ha/Ga*y(4))/(6/(E1tilde*h1^2));
d7ydx7 = Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*y(6) - Eatilde/ha*12/(E1tilde*h1^3)*y(4) + (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*y(2);
dydx = [y(2);y(3);y(4);y(5);y(6);y(7);d7ydx7;y(1);sigma;x*sigma];
end
function res = bcfcn(ya,yb,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2)
d2sigma_a = ((4/(E1tilde*h1)+2/(E2tilde*h2))*ya(4) - ha/Ga*ya(6))/(6/(E1tilde*h1^2));
d2sigma_b = ((4/(E1tilde*h1)+2/(E2tilde*h2))*yb(4) - ha/Ga*yb(6))/(6/(E1tilde*h1^2));
res = [ya(8);yb(8)+P;ya(9);yb(9);ya(10);yb(10)-P*(h1+ha)/2;d2sigma_a;d2sigma_b;ya(2)-Ga/ha*P/(E1tilde*h1);yb(2)+Ga/ha*2*P/(E2tilde*h2)];
end
  댓글 수: 7
Torsten
Torsten 2023년 4월 18일
편집: Torsten 2023년 4월 18일
Try this code whether you get a different result.
It's the analytical solution of your equation.
% Set model parameters
l = 25;
P = 100;
Ga = 1071;
Eatilde = 3000;
ha = 0.3;
E1tilde = 1;
h1 = 5;
E2tilde = 75000;
h2 = 5;
syms x tau(x)
% Solve differential equation
eqn = diff(tau,x,7) - Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*diff(tau,x,5) + Eatilde/ha*12/(E1tilde*h1^3)*diff(tau,x,3) - (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*diff(tau,x) == 0;
tau = dsolve(eqn)
tau0 = tau;
tau1 = diff(tau,x);
tau2 = diff(tau,x,2);
tau3 = diff(tau,x,3);
tau4 = diff(tau,x,4);
tau5 = diff(tau,x,5);
tau6 = diff(tau,x,6);
tau7 = diff(tau,x,7);
sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*tau1 - ha/Ga* tau3)/(6/(E1tilde*h1^2));
sigma2 = diff(sigma,x,2);
% Solve for free parameters in solution from boundary conditions
cond1 = int(tau0,x,-1,1) == -P;
cond2 = int(sigma,-l,l) == 0;
cond3 = int(x*sigma,-l,l) == P*(h1+ha)/2;
cond4 = subs(sigma2,x,-l) == 0;
cond5 = subs(sigma2,x,l) == 0;
cond6 = subs(tau1,x,-l) == Ga/ha*P/(E1tilde*h1);
cond7 = subs(tau1,x,l) == -Ga/ha*2*P/(E2tilde*h2);
[A,b] = equationsToMatrix([cond1 cond2 cond3 cond4 cond5 cond6 cond7]);
coeffs = (double(A)\double(b)).';
%Insert boundary conditions in general solution
vars = symvar(tau)
tau0num = subs(tau0,vars(1:7),coeffs);
tau1num = subs(tau1,vars(1:7),coeffs);
tau2num = subs(tau2,vars(1:7),coeffs);
tau3num = subs(tau3,vars(1:7),coeffs);
tau4num = subs(tau4,vars(1:7),coeffs);
tau5num = subs(tau5,vars(1:7),coeffs);
tau6num = subs(tau6,vars(1:7),coeffs);
tau7num = subs(tau7,vars(1:7),coeffs);
sigmanum = subs(sigma,vars(1:7),coeffs);
sigma2num = subs(sigma2,vars(1:7),coeffs);
% Check solution
double(int(tau0num,x,-l,l)+P)
double(int(sigmanum,x,-l,l))
double(int(x*sigmanum,-l,l) - P*(h1+ha)/2)
double(subs(sigma2num,x,-l))
double(subs(sigma2num,x,l))
double(subs(tau1num,x,-l)-Ga/ha*P/(E1tilde*h1))
double(subs(tau1num,x,l)+Ga/ha*2*P/(E2tilde*h2))
error = tau7num - Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*tau5num + Eatilde/ha*12/(E1tilde*h1^3)*tau3num - (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*tau1num;
% Plot solution
figure(1)
fplot(error,[-l l])
figure(2)
fplot(tau0num,[-l l])
figure(3)
fplot(sigmanum,[-l l])
Torsten
Torsten 2023년 4월 21일
편집: Torsten 2023년 4월 21일
Since I cannot run this code with MATLAB online (it takes too long), I'd be interested whether it gives a different result than the numerical approach. Could you give a short feedback ?

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추가 답변 (1개)

Torsten
Torsten 2023년 4월 13일
이동: Torsten 2023년 4월 13일
A symbolic approach will lead you nowhere because you had to solve for the general roots of a polynomial of degree 7 which is impossible.
So think about a numerical approach.
In order to cope with the integral boundary conditions, I suggest you additionally solve for the functions
F1(y) = integral_{x=-l}^{x=y} tau dx
F2(y) = integral_{x=-l}^{x=y} sigma*x dx
by solving
dF1/dx = tau(x)
dF2/dx = sigma(x)*x
with the boundary conditions
F1(-l) = 0
F1(l) = -P
F2(-l) = 0
F2(l) = P/2 * (h_1+h_a)
Try bvp4c or bvp5c for a solution.
  댓글 수: 4
Francesco Marchione
Francesco Marchione 2023년 4월 13일
@Torsten yes I can define the values for all the parameters involved. The unknown parameters are just tau and sigma. Can you please help me in writing the code to solve and plot the results?
Torsten
Torsten 2023년 4월 14일
Look at the examples under
They should show you how to proceed.
If you encounter problems somewhere with your code, you can come back here to ask.

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