Error msg in fminbnd

조회 수: 2 (최근 30일)
nirwana
nirwana 2023년 3월 16일
댓글: nirwana 2023년 3월 16일
Hi all
I an trying to find minimum value of function using fminbnd sing this script
x=linspace (0,6);
y=6*cos(x)+1.5*sin(x);
plot (y);
[xmin,fval]=fminbnd(y,2,4)
Error using fcnchk
FUN must be a function, a valid character vector expression, or an inline function object.

Error in fminbnd (line 198)
funfcn = fcnchk(funfcn,length(varargin));
But it give me an error mgs as shown, i don't understand what part in my code that have mistake.

채택된 답변

AL
AL 2023년 3월 16일
fun = @(x) 6*cos(x) + 1.5*sin(x); % Define the function
x_min = fminbnd(fun, 0, 6); % Find the minimum within the interval [0,6]
y_min = fun(x_min); % Evaluate the function at the minimum x value
plot(linspace(0,6), fun(linspace(0,6))); % Plot the function
hold on
plot(x_min, y_min, 'ro'); % Mark the minimum point on the plot
hold off
disp(['The minimum value of y is ', num2str(y_min), ' at x = ', num2str(x_min)]);
Try this Once.
  댓글 수: 3
John D'Errico
John D'Errico 2023년 3월 16일
fminbnd solves for the minimum of a FUNCTION. When you define x as a vector, then create y, as a VECTOR, y is just a list of numbers. It is not a function anymore, so fminbnd must fail.
What @AL did was create fun as a function. And now it works.
nirwana
nirwana 2023년 3월 16일
Thanks a lot @John D'Errico. Now I understand

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 MATLAB에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by