H = 0.1;
I = 5;
Y = 0;
BI = zeros(I,1);
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),pi*i);
BI(i) = b ;
end
X = linspace(0,1,I);
Theta = zeros(I,1);
for k = 1:length(X)
for m = 1:BI
Ts = sum(((((1/BI).*(1-cos(BI)))/(0.5-(1/(4.*BI)))).*sin(BI.*Y).*(cosh(2.*BI.*(X))-tanh(2.*BI).*sinh(2.*BI.*(X)))));
end
end
I'd like to:
  • Start at X =0
  • Sum Ts for all values of BI
  • Step to next value of X
  • Sum Ts for all values of BI
  • etc.

 채택된 답변

Edoardo_a
Edoardo_a 2023년 3월 7일
편집: Edoardo_a 2023년 3월 7일

0 개 추천

Hi, do you mean something like that?
In this case I sum all the values in the same Ts variable for all the X entry.
If you want to save a different Ts sum for each X entry then you should preallocate and store each Ts from the for loop.
H = 0.1;
I = 5;
Y = 1;
BI = zeros(I,1);
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),pi*i);
BI(i) = b ;
end
X = linspace(0,1,I);
Theta = zeros(I,1);
Ts = zeros(1);
for k = 1:length(X)
for m = 1:length(BI)
Ts =Ts + ((((1/BI(m)).*(1-cos(BI(m))))/(0.5-(1/(4.*BI(m))))).*sin(BI(m).*Y).*(cosh(2.*BI(m).*(X(k)))-tanh(2.*BI(m)).*sinh(2.*BI(m).*(X(k)))));
end
end

댓글 수: 1

H = 0.1;
I = 5;
Y = 1;
BI = zeros(I,1);
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),pi*i);
BI(i) = b ;
end
X = linspace(0,1,I);
Theta = zeros(I,1);
Ts = zeros(1);
for k = 1:length(X)
for m = 1:length(BI)
Ts(m) = ((((1/BI(m)).*(1-cos(BI(m)*pi/180)))/(0.5-(1/(4.*BI(m))))).*sin(BI(m)*(pi/180).*Y).*(cosh(2.*BI(m)*(pi/180).*(X(k)))-tanh(2.*BI(m)*pi/180).*sinh(2.*BI(m)*(pi/180).*(X(k)))));
%->>
end
TS(k) = sum(Ts);
end
TS
TS = 1×5
0.0030 0.0029 0.0028 0.0027 0.0027
You can do store the Ts values for each BI iteration using its index, and sum the Ts variable later. Also, input values to trigonometric functions, need to be in radians, for which you can multply with pi/180

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