How to solve an equation contains norminv?

조회 수: 3 (최근 30일)
Susan
Susan 2023년 2월 28일
댓글: Susan 2023년 3월 1일
Hi all,
I'd like to solve the following equation.
sol = [];
for L = -20:10:120
syms x
eqn = 10*log10(10.^(0.1*(norminv(x)*7.6 + 9.88)) + 10.^(0.1*(norminv(x)*6.5 + 12.1)) + 10.^(-0.3)) == L
S = solve(eqn);
sol = [sol S];
end
I modified the equation by replacing the norminv (x) with -sqrt(2)*erfcinv(2*x), i.e.,
sol = [];
for L = -20:10:120
syms x
eqn = 10*log10(10.^(0.1*(-sqrt(2)*erfcinv(2*x)*7.6 + 9.88)) + 10.^(0.1*(-sqrt(2)*erfcinv(2*x)*6.5 + 12.1)) + 10.^(-0.3)) == L
S = solve(eqn);
sol = [sol S];
end
However, I got a warning saying, "Warning: Unable to find explicit solution. For options, see help.". So, I add the following lines, hoping to solve the equation, but still unsuccessful.
S = solve(eqn);
string(lhs(eqn)-rhs(eqn))
sol = [sol vpasolve(eqn, [-143, -109.5937])]
Could someone please help me out?
Thanks in advance

채택된 답변

Walter Roberson
Walter Roberson 2023년 2월 28일
syms x
eqn = 10*log10(10.^(0.1*(-sqrt(2)*erfcinv(2*x)*7.6 + 9.88)) + 10.^(0.1*(-sqrt(2)*erfcinv(2*x)*6.5 + 12.1)) + 10.^(-0.3))
eqn = 
double(limit(eqn, x, 1e-200))
ans = -3.0000
double(limit(eqn, x, 1-sym(1e-50)))
ans = 123.5352
The left hand side is the same for all of them, and you cannot get it down below -3 and cannot get it much above 120-ish. So there is no real-valued solution for L = -20 or L = -10
For the other values... use vpasolve() with around 0.01 as an initial guess, and after that use the previous solution as the initial guess for the next round.
  댓글 수: 9
Susan
Susan 2023년 3월 1일
@Walter Roberson Got you! Thans again

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Numbers and Precision에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by