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Need a to plot a graph

조회 수: 2 (최근 30일)
Julia Sabetti
Julia Sabetti 2023년 1월 25일
편집: Torsten 2023년 1월 25일
close all; clear;
h = input('height of water in tank = ');
Unable to run the 'fevalJSON' function because it calls the 'input' function, which is not supported for this product offering.
H1 = 11; %in
H2 = 5; %in m
r1 = 3.5; %in m
r2 = 6; %in m
if h < 0
Vtotal = 0;
elseif h < 11
Vtotal = pi*r1*r1*h; % Volume of water in tank in m^3
else
rh = r1+((h-H1)*(r2-r1))/H2;
Vtotal = pi*r1*r1*H1+(pi*(h-H1)*(r1*r1+r1*rh+rh*rh))/3; % Volume of water in tank in m^3
end
plot(h,Vtotal)
I dont know how to plot the graph from h = 0 to 17. I am just not sure what needs to be changed in the code. Thank you
  댓글 수: 1
Torsten
Torsten 2023년 1월 25일
편집: Torsten 2023년 1월 25일
So the tank is a cylinder with radius r1 for 0 <= h <= H1, followed by a frustrum of height H2 with lower radius r1 and upper radius r2 ?
Then you still have to distinguish the cases h <= H1 + H2 and h > H1 + H2.

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답변 (2개)

Walter Roberson
Walter Roberson 2023년 1월 25일
hvals = linspace(0,17);
numh = length(hvals);
Vtotal = zeros(numh, 1);
H1 = 11; %in
H2 = 5; %in m
r1 = 3.5; %in m
r2 = 6; %in m
for hidx = 1 : numh
h = hvals(hidx);
if h < 0
Vtotal(hidx) = 0;
elseif h < 11
Vtotal(hidx) = pi*r1*r1*h; % Volume of water in tank in m^3
else
rh = r1+((h-H1)*(r2-r1))/H2;
Vtotal(hidx) = pi*r1*r1*H1+(pi*(h-H1)*(r1*r1+r1*rh+rh*rh))/3; % Volume of water in tank in m^3
end
end
plot(hvals,Vtotal)

Michael Habermann
Michael Habermann 2023년 1월 25일
편집: Michael Habermann 2023년 1월 25일
close all; clear;
H1 = 11; %in
H2 = 5; %in m
r1 = 3.5; %in m
r2 = 6; %in m
h_low = 0:11
h_low = 1×12
0 1 2 3 4 5 6 7 8 9 10 11
Vtotal_low = pi*r1*r1*h_low % Volume of water in tank in m^3
Vtotal_low = 1×12
0 38.4845 76.9690 115.4535 153.9380 192.4226 230.9071 269.3916 307.8761 346.3606 384.8451 423.3296
h_high = 12:17
h_high = 1×6
12 13 14 15 16 17
rh = r1+((h_high-H1).*(r2-r1))./H2
rh = 1×6
4.0000 4.5000 5.0000 5.5000 6.0000 6.5000
Vtotal_high = pi*r1*r1*H1+(pi.*(h_high-H1).*(r1*r1+r1.*rh+rh.*rh))/3 % Volume of water in tank in m^3
Vtotal_high = 1×6
467.5737 524.3842 595.3318 681.9874 785.9218 908.7057
h = [h_low, h_high]
h = 1×18
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
Vtotal = [Vtotal_low, Vtotal_high]
Vtotal = 1×18
0 38.4845 76.9690 115.4535 153.9380 192.4226 230.9071 269.3916 307.8761 346.3606 384.8451 423.3296 467.5737 524.3842 595.3318 681.9874 785.9218 908.7057
plot(h,Vtotal)

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