I wrote this code but it takes a lot time to run even though it's not running.
조회 수: 1 (최근 30일)
이전 댓글 표시
clc;
clear;
ti = 0;
tf = 70E-6;
tspan=[ti tf];
k = 7E-6;
h = 1E-2;
for j = 1:100
y0= [(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
((-3.14).*rand(20,1) + (3.14).*rand(20,1));
rand(1,1);
];
yita_mn = [
0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1;
1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1;
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
];
N = 20;
tp = 1E-9;
o = sort(10e2*rand(1,20),'ascend');
[T,Y]= ode45(@(t,y) rate_eq(t,y,yita_mn,N,o,k),[0:1E-8:70E-6]./tp,y0);
r = ((1/20).*( exp(i.*Y(:,3)) + exp(i.*Y(:,6)) + exp(i.*Y(:,9)) + exp(i.*Y(:,12)) + exp(i.*Y(:,15)) ...
+exp(i.*Y(:,18)) +exp(i.*Y(:,21)) +exp(i.*Y(:,24)) + exp(i.*Y(:,27)) + exp(i.*Y(:,30)) + exp(i.*Y(:,33)) ...
+ exp(i.*Y(:,36)) + exp(i.*Y(:,39)) +exp(i.*Y(:,42)) + exp(i.*Y(:,45)) + exp(i.*Y(:,48)) + exp(i.*Y(:,51)) + exp(i.*Y(:,54))+ exp(i.*Y(:,57)) + exp(i.*Y(:,60))));
figure(j)
M = (abs(r));
plot(T,M)
end
function dy = rate_eq(t,y,yita_mn,N,o,k)
dy = zeros(4*N+1,1);
dGdt = zeros(N,1);
dAdt = zeros(N,1);
dOdt = zeros(N,1);
P = 0.80;
a = 0;
T = 1500;
tp = 1E-9;
Gt = y(1:3:3*N-2);
At = y(2:3:3*N-1);
Ot = y(3:3:3*N-0);
for i = 1:N
dGdt(i) = (P - Gt(i) - (1 + 2.*Gt(i)).*((At(i)))^2)./T ;
dAdt(i) = Gt(i)*(At(i));
dOdt(i) = a.*Gt(i) + o(1,i).*tp;
for j = 1:N
dAdt(i) = dAdt(i) + (y(81)).*yita_mn(i,j)*(At(j))*cos(Ot(j)-Ot(i));
dOdt(i) = dOdt(i) + (y(81)).*yita_mn(i,j)*((At(j)/At(i)))*sin(Ot(j)-Ot(i));
end
end
dy(1:3:3*N-2) = dGdt;
dy(2:3:3*N-1) = dAdt;
dy(3:3:3*N-0) = dOdt;
n1 = (1:20)';
n2 = circshift(n1,-1);
n61 = n1 +60;
n62 = circshift(n61,-1);
n80 = circshift(n61,1);
j2 = 3*(1:20)-1;
j5 = circshift(j2,-1);
j8 = circshift(j2,-2);
j59 = circshift(j2,1);
dy(n61) = (o(1,n2).' - o(1,n1).').*tp + a.*(Gt(n2) - Gt(n1)) - (y(81)).*(y(j2)./y(j5)).*sin(y(n61)) - (y(81)).*(y( j5)./y(j2)).*sin(y(n61)) + (y(81)).*(y(j8)./y(j5)).*sin(y(n62)) + (y(81)).*(y(j59)./y(j2)).*sin(y(n80));
dy(81) = k;
end
댓글 수: 5
Torsten
2023년 1월 17일
Add the line
disp(t)
right after the function line
function dy = rate_eq(t,y,yita_mn,N,o,k)
When the code gets stuck at a certain time, stop the code, change tspan with a value for tend some instant before the time the code got stuck and inspect the results at tend to find the reason for failure.
답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!