Loop through multiple columns in table using if condition

I have a large table, let's call it X, with many rows and columns. I want to loop through 10 columns (named X.A, X.B, X.C, etc.), and when all of the 10 columns for a specific row have the value NaN, I want a 0 in the column X.result, and when at least one or more of the columns has a value (an integer), I want it to return a 1 in the column X.result.

I tried to create this with looping through 1 column first and add more after, but I can't seem to manage it to work:

for i = 1:length(X.result)

if (~isnan((X.A)))

X.result(i) = 1;

end

end

I think I might be doing something wrong in defining variables but I can't seem to figure it out. The first line after the if statement ( if (~isnan((X.A))) ) works, but no 0 or 1 is assigned to the X.result column. Can anybody help me with this? Thanks!

Answer 1

[VBBV]

X.A = [randi([0 10],1,7) NaN]

X = struct with fields:
    A: [2 10 7 7 3 4 8 NaN]

X.B = repmat(NaN,1,8);
for i = 1:length(X.A) 
      if (isnan(X.A(i)) & isnan(X.B(i)))
         X.result(i) = 0;         
      elseif ~isnan(X.A(i)) | ~isnan(X.B(i))
         X.result(i) = 1;          
      end
end
[X.A.', X.B.', X.result.']

ans = 8×3

2 NaN 1 10 NaN 1 7 NaN 1 7 NaN 1 3 NaN 1 4 NaN 1 8 NaN 1 NaN NaN 0

[VBBV]

extend the condition /check you have inside the loop, upto 10 columns as

if (isnan(X.A(i)) & isnan(X.B(i))) & isnan(X.C(i)) ... so on 

[YaaW]

Thanks! Keep forgetting to put the (i) behind the variable :)