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I need to plot eigen values with Imaginary axis in log scales?

조회 수: 4 (최근 30일)
Siddhant Maurya
Siddhant Maurya 2022년 12월 8일
댓글: Siddhant Maurya 2023년 1월 31일
Need help to plot eigen values with Imaginary axis in log scales?
  댓글 수: 2
Siddhant Maurya
Siddhant Maurya 2022년 12월 8일
otherwise plotting eigen values with real axis in log scales will also do?
Jonas
Jonas 2022년 12월 8일
so whats the problem here?
someComplex=rand(5,1)+1i*rand(5,1)
someComplex =
0.6257 + 0.8031i 0.8168 + 0.6693i 0.8646 + 0.1120i 0.9827 + 0.4830i 0.4358 + 0.2156i
plot(someComplex,'x');
set(gca,'YScale','log');
xlabel('real part');
ylabel('imaginary part (i)')

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답변 (1개)

Gobiha Duraisamy
Gobiha Duraisamy 2022년 12월 22일
Currently, there is no direct function to plot one of the axis in log scale. As a workaround, you can set the appropriate scale to "log" as follows,
lamda = -rand(3,1)+1i*rand(3,1) % create three random set of eigenvalues
lamda =
-0.6889 + 0.2015i -0.9937 + 0.1999i -0.7680 + 0.2688i
plot(lamda,'o','LineWidth',3)
set(gca,'YScale','log')
grid on;
If you want to set the real part in log scale, use the following line of codes instead,
plot(lamda,'o','LineWidth',3)
set(gca,'XScale','log')
grid on;
Both X and Y coordinates are plotted in log scale using "loglog" function as follows,
loglog(lamda,'o','LineWidth',3)
grid on;
  댓글 수: 2
Jonas
Jonas 2023년 1월 21일
"Currently, there is no direct function to plot one of the axis in log scale." thats not true, look into semilogx() and semilogy()
Siddhant Maurya
Siddhant Maurya 2023년 1월 31일
It doesn't work. Try taking complex number in all 4 quadrants and then plot them.

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