Hello, I have a structure array which consists of 39 variables (LFHD, RFHD, etc.) Each of those variables contains 3 double arrays of size 1 x ?. I would like to interpolate those double arrays from 1 x ? to 1 x 101 (0-100%) so that they are all the same length and I can average across them.
I am a bit of a MATLAB novice. Any assistance would be greatly appreciated.

 채택된 답변

Matt J
Matt J 2022년 11월 28일

0 개 추천

fcn=@(f)interp1(f, linspace(1,numel(f),101) );
for i=1:numel(TrajXLstance)
TrajXLstance(i) = structfun(fcn, TrajXLstance(i),'uni',0);
end

댓글 수: 6

Josh Tome
Josh Tome 2022년 11월 28일
This is great! Thank you. Can I ask what the "f" represents?
Josh Tome
Josh Tome 2022년 11월 28일
Sorry for the 2nd question before you answer the 1st, but I have another structure array similar to the OP, but instead of 1 x ? double arrays it has 3 x ? double arrays. When I try the same code, instead of interpolating the ? number, it interpolates the 3, so I end up with double arrays of size 101 x ?. Any thoughts?
Can I ask what the "f" represents?
It represents the value of a struct field.
When I try the same code, instead of interpolating the ? number, it interpolates the 3
Transpose:
fcn=@(f)interp1(f.', linspace(1,numel(f),101) ).';
Josh Tome
Josh Tome 2022년 11월 28일
when I use the transpose on the 3 x ? double arrays at first glance it appeared to work by creating arrays of 3 x 101. However, looking closely at these arrays it compressed the actual data by half, and then filled the rest of the 101 points with NAN's. For instance a 3 x 66 array of data was converted into a 3 x 33 array of data with the last 3 x 68 array of NANs. Any idea why that would happen?
Try this insead,
fcn=@(f)interp1(f.', linspace(1, size(f,2) ,101) ).';
Josh Tome
Josh Tome 2022년 11월 29일
Yes, that seems to work. Thanks again for your help!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

질문:

2022년 11월 28일

댓글:

2022년 11월 29일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by