Erro in calling function using horner()

조회 수: 3 (최근 30일)
Lucas
Lucas 2022년 11월 28일
편집: Torsten 2022년 11월 28일
I wrote the following code to fild the roots of a given function. In program, the example function ig given by f(x) = x^3-6x^3+11x-6. When I compile the code the following messages appears:
Incorrect number or types of inputs or outputs for function 'horner'.
Error in test>newtonhorner (line 34)
[pz,b] = horner(a,x);
Error in test (line 4)
a = [1 -6 11 -6]; [x,niter]=newtonhorner(a,0,1.e-15,100);
How can I solve this? Thanks if anyone can help!
My code:
a = [1 -6 11 -6]; [x,niter]=newtonhorner(a,0,1.e-15,100);
function [roots , iter]= newtonhorner(a,x0,tol,nmax)
%NEWTONHORNER Newton - Horner method
% [roots , ITER]= NEWTONHORNER(A,X0) computes the roots of
% polynomial
% P(X) = A(1)*X^N + A(2)*X^(N-1) + ... + A(N)*X +
% A(N+1)
% using the Newton - Horner method starting from the
% initial datum X0. The method stops for each root
% after 100 iterations or after the absolute value of
% the difference between two consecutive iterates is
% smaller than 1.e-04.
% [roots , ITER]= NEWTONHORNER(A,X0 ,TOL , NMAX) allows to
% define the tolerance on the stopping criterion and
% the maximal number of iterations.
if nargin == 2
tol = 1.e-04; nmax = 100;
elseif nargin == 3
nmax = 100;
end
n=length(a)-1;
roots = zeros (n,1);
iter = zeros(n,1);
for k = 1:n
% Newton iterations
niter = 0; x = x0; diff = tol + 1;
while niter <= nmax & diff >= tol
[pz,b] = horner(a,x);
[dpz,b]= horner(b,x);
xnew = x - pz/dpz;
diff = abs(xnew -x);
niter = niter + 1;
x = xnew;
end
if niter >= nmax
fprintf('Fails to converge within maximum ',...
'number of iterations\n ');
end
% Deflation
[pz ,a] = horner(a,x); roots(k) = x; iter(k) = niter;
end
return
end

채택된 답변

Torsten
Torsten 2022년 11월 28일
편집: Torsten 2022년 11월 28일
I don't understand what you intend by using the lines
[pz,b] = horner(a,x);
[dpz,b]= horner(b,x);
[pz ,a] = horner(a,x)
They will error because of two reasons:
a and b must be symbolic polynomials.
"horner" has only one output, namely the input polynomial in horner form.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Tables에 대해 자세히 알아보기

제품


릴리스

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by