Eliminate a for loop to increase speed

조회 수: 3 (최근 30일)
Howard Wilton
Howard Wilton 2022년 11월 23일
댓글: Howard Wilton 2022년 11월 25일
I have a code snippet below which uses a for loop that I am trying to eliminate as I need to scale up to larger values of N and L.
clc; clearvars;
N = 2; L = 2; T = 1;
a = [1 1i; -1i -1];
nplq = int8(de2bi((0:2^(N*L)-1),'left-msb')); % [0 0 0 0; 0 0 0 1; 0 0 1 0; ... ; 1 1 1 1]
a_nl = zeros(2^(N*L),1);
for i = 1:2^(N*L)
a_nl(i) = a(nplq(i,1)+1,nplq(i,3)+1);
end
% wish i could do something like a_nl = a(nplq(:,1),nplq(:,3))
Any suggestions would be appreciated.

채택된 답변

Jan
Jan 2022년 11월 23일
편집: Jan 2022년 11월 23일
N = 2; L = 2; T = 1;
a = [1 1i; -1i -1];
nplq = int8(de2bi((0:2^(N*L)-1),'left-msb')); % [0 0 0 0; 0 0 0 1; 0 0 1 0; ... ; 1 1 1 1]
a_nl = zeros(2^(N*L),1);
for i = 1:2^(N*L)
a_nl(i) = a(nplq(i,1) + 1, nplq(i,3) + 1);
end
% Without a loop:
a_nl2 = a(sub2ind(size(a), nplq(:,1) + 1, nplq(:,3) + 1));
isequal(a_nl, a_nl2) % Same result?
ans = logical
1
Do you really need the complete nplq matrix or are the 2 columns enough?
N = 2; L = 2;
M = 2^(N*L - 1)
v = uint8(1:2).';
nplq1 = repelem(v, M, 1);
c = 3 - 1; % 3rd column
nplq3 = repmat(repelem(v, M / 2^c, 1), 2^c, 1);
  댓글 수: 3
Jan
Jan 2022년 11월 24일
The creation of nplq can be expensive, if it exhausts the free memory: It is created as double at first, which needs 8 times the RAM of the needed UINT8 array. If this is a problem, you can try the C-mex function: FEX: VChoseKRO:
VChooseKRO_M(uint8([0,1]), N*L)
Howard Wilton
Howard Wilton 2022년 11월 25일
Thank you very much!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Whos에 대해 자세히 알아보기

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by