Plot a Signal Function

I am trying to plot a signal in Matlab for

-1.5≤dt≤1.5:

x(t) = sin(pi*t)rect(t)

where rect(t) is the rect function.

and I am trying to obtain and plot the magnitude of 𝑋(𝑓) the Fourier transform of 𝑥(𝑡) of that.

[Walter Roberson]

dt can be negative? Your difference between time steps can be negative?? (You have a bit of a meaning question about what exactly should happen for the case where dt = 0, where all times are exactly the same.)

[Walter Roberson]

https://www.mathworks.com/matlabcentral/answers/68012-rectangular-function-implementation-in-matlab#answer_79386

Answer 1

[Sina]

clear all

close all

clc

fs= 600; %This Sampling Frequency

dt = 0.001;

T = -1.5:dt:1.5;

fs=1/dt;

f=(-1/2:1/length(T):1/2-1/(length(T)*2))*fs;

y=sin(pi*T).*rectangularPulse(T);

yf = fftshift(fft(y));

z=abs(yf);

plot(f, z);

title("Plot for the Signal");

xlabel("Frequency")

ylabel("X(f):the Fourier transform of 𝑥(𝑡)")

[Walter Roberson]

Note that rectangularPulse requires the Symbolic Toolbox