no puedo plotear en mi codigo
조회 수: 1 (최근 30일)
이전 댓글 표시
%R1=3;% radio de las bandas
%R2=2;
bi=1; %espaciado;
%h=100;
%descenso
tr=linspace(pi,0,100);
tr1=linspace(2*pi,pi,100);
tr12=linspace(pi,0,100);
%elipse externa
a=[3*cos(tr) 3*cos(tr1)];
b=[3*sin(tr) 3*sin(tr1)-6];
%interna
a1=[2*cos(tr) 2*cos(tr1)];
b1=[2*sin(tr) 2*sin(tr1)-6];
% la separacion para cada banda es = b
c=[(bi*tr12)/2*pi];
c=[c+14 c+13 c+12 c+11 c+10 c+9 c+8 c+7 c+6 c+5 c+4 c+3 c+2 c+1];
%ascenso
tr2= linspace(0,pi,100); tr22=linspace(pi,2*pi,100); tr23=linspace(0,pi,100);
a2=[3*cos(tr2) 3*cos(tr22)];
b2=[3*sin(tr2) 3*sin(tr22)-4];
%interna
a3=[2*cos(tr2) 2*cos(tr22)];
b3=[2*sin(tr2) 2*sin(tr22)-6];
%separacion es de 2
c1=[(bi*tr23)/(2*pi)];
c1=[c1+0 c1+2 c1+4 c1+6 c1+8 c1+10 c1+12 c1+14];
for i=1:3
a=[a a];
b=[b b];
a1=[a1 a1];
b1=[b1 b1];
a2=[a2 a2];
b2=[b2 b2];
a3=[a3 a3];
b3=[b3 b3];
end
%linea cruzada
tz=linspace (0,pi/4,100);
tz1=linspace(pi/4,pi/2,100);
a4=[3*cos(tz) cos(3*pi/2)-tz1];
b4=[3*sin(tz)-6 sin((3*pi/2)-tz1)];
a5=[cos(tz) 3*cos((3*pi/2)-tz1)];
b5=[sin(tz)-6 3*sin((3*pi/2)-tz1)];
c2=c1(end)*ones(1,200);
%graficas
plot3(a2,b2,c1,'r');
hold on
plot3(a3,b3,c1,'m');
plot3(a,b,c,'r');
hold on
plot3(a1,b1,c,'b');
plot3(a4,b4,c2,'g');
plot3(a5,b5,c2,'c');
xlim([-3 3]);
xlabel('axis x')
ylabel('axis y')
zlabel('axis z')
title('banda transportadora')
hold off
댓글 수: 1
Jan
2022년 10월 30일
I've included the error message in the question. It is easier to solve a problem than to guess, what the problem is.
답변 (1개)
Gokul Nath S J
2023년 5월 26일
Hi Ricardo,
It seems that you are receving an error mentioning the vectors are of different length. The variable c1 is of length 800 while the other variables a2 and b2 are 1600. Please note that this difference is attributed to the fact that you are concatinating two matrixes together in the following lines.
a2=[3*cos(tr2) 3*cos(tr22)];
b2=[3*sin(tr2) 3*sin(tr22)-4];
Since the objective of the function is not mentioned in the question, as I workaround, I would suggest you check the dimension of the a2, b2 and c1 variable and understand whether there is a requirement for the concatenation or you might have missed the concatination of the variable c1.
with regards,
Gokul Nath S J
댓글 수: 0
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