need plot a graph using Euler's method for both numerical and analytical
이전 댓글 표시
% Euler's Method
% Initial conditions and setup
h = (10); % step size
x = (0):h:(60); % the range of x
y = zeros(size(x)); % allocate the result y
y(1) = (2); % the initial y value
n = numel(y); % the number of y values
for i=1:n-1
pi = 3.1416
a = 2
r = 1
f = a + (2 - 0.4*a) * x / r^2 * pi
y(i+1) = y(i) + h * f;
end
plot (x,y,'b')
grid on
댓글 수: 4
Why do you think you need to define a value for pi? And worse, the value you chose is not even very accurate? Of course you are using Euler's method, with an extremely coarse step size. So 5 digits fo pi is probably adequate. But learn tol leave pi alone. It already exists. So there is no need to define it as a variable.
format long g
pi
And that is the correct value out to that many digits.
But you seem to be plotting the numrical solution. So what is your problem? What is the differential equation? Can you integrate that analytically? Surely, since f is LINEAR in x, you know the integral, since the integral of x is x^2/2? Or you could use dsolve in the symbolic toolbox?
Do you need to know how to add a second plot to the existing figure?
help hold
Jan
2022년 10월 29일
Avoid to define constants inside a loop. Although runtime does not matter here, it is worth to start programming with a clean and clear style.
Enclosing constants in parentheses is clutter. 0:h:60 is fine.
You have mentioned your goal and posted some code. To get a proper answer, ask a specific question. What is the problem?
Mpho Mokgotlo
2022년 10월 30일
Jan
2022년 10월 30일
@Mpho Mokgotlo: If you mention an error, post a copy of the complete error message. Seeing some parts of the message only is less useful, e.g. the readers do not know, in which line the error occurs.
답변 (2개)
Alan Stevens
2022년 10월 30일
편집: Jan
2022년 10월 30일
f = a + (2 - 0.4*a) * x(i) / r^2 * pi; % x(i) not just x.
% Also take note of the other comments above.
댓글 수: 1
Jan
2022년 10월 30일
I've moved this to an answer, because it solves a problem.
Jan
2022년 10월 30일
h = 10; % step size
x = 0:h:60; % the range of x
y = zeros(size(x)); % allocate the result y
y(1) = 2; % the initial y value
n = numel(y); % the number of y values
a = 2;
r = 1;
for i = 1:n-1
f = a + (2 - 0.4 * a) * x(i) / r^2 * pi;
% ^^^
y(i+1) = y(i) + h * f; % I guess this line fails
end
plot (x,y,'b')
grid on
A cleaned version of your code. Alan Stevens' hint is included (please accept his answer).
You can solve such problems using the debugger. Type in the command window:
dbstop if error
and run the code again. Matlab stops at the problem and you can check the values of the used variables.
size(y(i+1)) % A scalar, of course
size(y(i) + h * f) % Not a scalar
size(f) % Same size as x!
You do not want x in the line to get the value of f, but only the element x(i).
Do you really mean: ... / r^2 * pi or .../ (r^2 * pi) ?
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