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problem in convolutional coding

조회 수: 4 (최근 30일)
tamim
tamim 2022년 10월 21일
댓글: Rik 2022년 10월 21일
i dont know what is the problem in this code:
% rate 1/2 convolutional encoder
% define trellis
trellis = poly2trellis(7,[171 133]);
% define input and output
x = randintrlv(1:100,3);
y = convenc(x,trellis);
Error using convenc
Expected MSG to be binary.

Error in convenc (line 88)
validateattributes(msg, {'numeric', 'logical'}, ...
% define generator polynomials
g1 = [1 0 1 0 1 1 1 0];
g2 = [1 1 1 0 1 1 0 1];
% encode
y1 = mod(conv(y,g1),2);
y2 = mod(conv(y,g2),2);
% interleave
z = [y1;y2];
z = z(:)';
% modulate
M = 4;
k = log2(M);
y_tx = bi2de(reshape(z,k,length(z)/k).','left-msb');
% plot constellation
scatterplot(y_tx,1,0,'k*');
axis([-5 5 -5 5]);
% add noise
EbNo = 10;
snr = EbNo + 10*log10(k) - 10*log10(log2(M));
y_rx = awgn(y_tx,snr,'measured');
% demodulate
z_rx = de2bi(y_rx,k,'left-msb');
% de-interleave
y1_hat = z_rx(1:2:end);
y2_hat = z_rx(2:2:end);
% decode
tblen = 15;
y_hat = vitdec(y1_hat,trellis,tblen,'trunc','hard');
% plot BER
ber = berawgn(EbNo,'psk',M,'nondiff');
semilogy(EbNo,ber,'k*');
hold on;
ber = berawgn(EbNo,'psk',M,'nondiff');
semilogy(EbNo,ber,'ko');
legend('Theoretical BER','Empirical BER');
xlabel('Eb/No (dB)');
ylabel('Bit Error Rate');
it shows this error:
Error using convenc
Expected MSG to be binary.
Error in convenc (line 88)
validateattributes(msg, {'numeric', 'logical'}, ...
Error in test2 (line 11)
y = convenc(x,trellis);
  댓글 수: 1
Rik
Rik 2022년 10월 21일
x = randintrlv(1:100,3)
x = 1×100
22 69 84 33 96 9 54 15 41 67 34 85 98 87 59 65 23 64 32 3 50 40 78 10 27 4 51 2 97 92
That isn't binary. Apparently the convenc function expects the input to be binary.
Why do you expect this to work?

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