Error While Saving the Raw data into Binary Image.

조회 수: 2(최근 30일)
Stephen john
Stephen john 2022년 10월 17일
댓글: Walter Roberson 2022년 10월 18일
Hello Everyone, I hope you are doing well. I have the code which make the data into Image format.
But the main issue with this code is that, When the same values of data comes it gives the error here is the error.
As i attached the 2 dataset below. The code works fine on dataset2.mat
While when we run it into dataset1.mat it gives the error.
Error using matlab.internal.math.interp1
Sample points must be unique.
Error in interp1 (line 188)
VqLite = matlab.internal.math.interp1(X,V,method,method,Xqcol);
The following is the code which i used
[numImages, lenImage] = size(Dataset1000);
% ImageSize
for imNum = 1:numImages
imData = Dataset1000(imNum,:); % get pattern
dataset=imData;
x=1:numel(dataset);%this is what you did implictly
y=dataset;
resolution=1000;
X=linspace(min(x), max(x) ,resolution);
Y=linspace(min(y), max(y) ,resolution);
% determine index in X of each x, likewise for y (note that the coordinates
% are flipped for the y-direction in images).
ind_x=interp1(X, 1:numel(X) ,x,'nearest');
ind_y=interp1(Y,numel(Y):-1:1,y,'nearest');
%compute linear index
ind=sub2ind([resolution resolution],ind_y,ind_x);
% create the image
IM=zeros(resolution,resolution);
IM(ind)=1;
% Since you apparently want a dilation, apply it before displaying the
% image.
SE=strel('disk',2);
im=imdilate(IM,SE);
end

답변(1개)

Walter Roberson
Walter Roberson 2022년 10월 17일
We talked to you about this already. Your min x and max x are the same so your linspace is all the same value.
There is no way to rescue the situation with a small code tweak. You need to go back and rethink what you are doing.
Have you considered using improfile()? It automatically switches between interpolation over x or over y to get the best results.
  댓글 수: 8
Walter Roberson
Walter Roberson 2022년 10월 18일
Computer Vision has insertShape and insertText. Between the two they can create any line graph (surfaces are harder)

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