sprintf into a number
    조회 수: 6 (최근 30일)
  
       이전 댓글 표시
    
Hello, 
I have the simple following code and it does not work of course as sprintf makes a string and cannot be entered as a value in the matrix.
Mat=zeros(64,64,round(Zlen));
for i = 1:64
    for j = 1:64
        for k = 1:Zlen
           Mat(i,j,k)=sprintf('Ch0%d_0%d(1,%d)', i, j, k)
        end
    end
end
I know how Matlab work and that I cannot just hope to supress the ' by magic but I have these Data Matrix that are name as the following Ch01_01 / Ch01_02 / ... / Ch01_64 / Ch02_01 / Ch02_02 / Ch02_64 / Ch03_01 / etc..
However I still cannot find a turnaround that issue. Could you help me ?
Thank you 
댓글 수: 5
  Stephen23
      
      
 2022년 10월 15일
				"What is stopping me is that when i open the .mat matrix, i have more than 4000 files opening in the workspace and to open them all with load command I would need a loop and call them one by one, coming back to my initial issue."
So far everything you describe sounds like it could be avoided by LOADing into an output variable, as already shown.
채택된 답변
  Jan
      
      
 2022년 10월 15일
        Stephen an Walter hit the point.
% Store imported data in an array instead of polluting the workspace:
FileData = load('YourInputFile.mat');
% No loop over k required:
Mat = zeros(64, 64, round(Zlen));
for i = 1:64
    for j = 1:64
        Mat(i, j, :) = FileData.(sprintf('Ch0%d_0%d', i, j));
    end
end
댓글 수: 0
추가 답변 (1개)
  Walter Roberson
      
      
 2022년 10월 12일
        Please read http://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval for information about why we strongly recommend against creating variable names dynamically.
댓글 수: 0
참고 항목
카테고리
				Help Center 및 File Exchange에서 Whos에 대해 자세히 알아보기
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!