Can anyone please help ?

조회 수: 24 (최근 30일)
Mohamed
Mohamed 2022년 10월 2일
편집: Walter Roberson 2024년 8월 9일
im trying to compute the steady solutions for the stream function and scalar vorticity for a 2d flow around an infinite cylinder at RE = 10
here is the question:
Here is the code:
function [psi, omega] = flow_around_cylinder_steady
Re=10;
%%%%% define the grid %%%%%
n=101; m=101; % number of grid points
N=n-1; M=m-1; % number of grid intervals
h=pi/M; % grid spacing based on theta variable
xi=(0:N)*h; theta=(0:M)*h; % xi and theta variables on the grid
%%%%% Initialize the flow fields %%%%%
psi=zeros(n,m);
omega=zeros(n,m);
psi(n,:)=exp(xi(n)) * sin(theta(:));
%%%%% Set relax params, tol, extra variables %%%%%
r_psi=1.8
r_omega=0.9
delta=1.e-08; % error tolerance
error=2*delta; % initialize error variable
%%%%% Add any additional variable definitions here %%%%%
...
...
%%%%% Main SOR Loop %%%%%
while (error > delta)
psi_old = psi; omega_old = omega;
for i=2:n-1
for j=2:m-1
psi(i,j)=exp(xi(i)) * sin(theta(j));
end
end
error_psi=max(abs(psi(:)-psi_old(:)));
omega(1,:)= (psi(3,j) - 8*psi(2,j)) * 1/(2*h^2);
for i=2:n-1
for j=2:m-1
omega_old(1,j)= (psi(3,j) - 8*psi(2,j)) * 1/(2*h^2);
end
end
error_omega=max(abs(omega(:)-omega_old(:)));
error=max(error_psi, error_omega);
end
plot_Re10(psi);
The code to call the function is:
[psi, omega] = flow_around_cylinder_steady;
But i get this:
The server timed out while running your solution. Potential reasons include inefficient code, an infinite loop, and excessive output. Try to improve your solution.
is there any way to improve it ?
  댓글 수: 4
Samson
Samson 2022년 11월 7일
Hi Mohamed,
I have exactly the same issue, and reviewed the class. and I don't see where is went wrong
did you solve it ?
Samson
Samson 2022년 11월 7일
omega_old seems to be one of the issue.. and my SOR doesnt seem to work /:

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답변 (1개)

Bhavesh Gyanchandani
Bhavesh Gyanchandani 2023년 7월 8일
편집: Walter Roberson 2024년 8월 9일
Here is the assignment code which i wrote
It is correct
function [psi, omega] = flow_around_cylinder_steady
Re=10;
%%%%% define the grid %%%%%
n=101; m=101; % number of grid points
N=n-1; M=m-1; % number of grid intervals
h=pi/M; % grid spacing based on theta variable
xi=(0:N)*h; theta=(0:M)*h; % xi and theta variables on the grid
%%%%% Initialize the flow fields %%%%%
psi=zeros(n,m);
omega=zeros(n,m);
psi(n,:)=exp(xi(n))*sin(theta(:)); % Write the free stream bc here
%%%%% Set relax params, tol, extra variables %%%%%
r_psi=1.8; % Set the relaxation parameter here, psi equation
r_omega=0.9; % Set the relaxation parameter here, omega equation
delta=1.e-08; % error tolerance
error=2*delta; % initialize error variable
%%%%% Add any additional variable definitions here %%%%%
...
...
%%%%% Main SOR Loop %%%%%
while (error > delta)
psi_old = psi; omega_old = omega;
for i=2:n-1
for j=2:m-1
psi(i,j)=(1-r_psi)*psi(i,j)+(r_psi/4)*(psi(i+1,j)+psi(i-1,j)+psi(i,j+1)+psi(i,j-1)+h*h*exp(2*xi(i))*omega(i,j));% Write psi equation here
end
end
error_psi=max(abs(psi(:)-psi_old(:)));
omega(1,:)=(psi(3,:) - 8*psi(2,:))/(2*h^2); % Write the boundary condition here
for i=2:n-1
for j=2:m-1
omega(i,j)=(1-r_omega)*omega(i,j)+(r_omega/4)*(omega(i+1,j)+omega(i-1,j)+omega(i,j+1)+omega(i,j-1)+(Re/8)*((psi(i+1,j)-psi(i-1,j))*(omega(i,j+1)-omega(i,j-1))-(psi(i,j+1)-psi(i,j-1))*(omega(i+1,j)-omega(i-1,j)))); % Write omega equation here
end
end
error_omega=max(abs(omega(:)-omega_old(:)));
error=max(error_psi, error_omega);
end
plot_Re10(psi);
  댓글 수: 4
SANTHOSH
SANTHOSH 2024년 8월 8일
but after run the function i couldnt be able to submit. it shows that " Variable psi has an incorrect value and Variable omega has an incorrect value"
SANTHOSH
SANTHOSH 2024년 8월 8일
@Bhavesh Gyanchandani. i got good plot. but after submitting it shows "Variable psi has an incorrect value and Variable omega has an incorrect value". can you pls help me to overcome this issue

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