The parfor loop cannot be run due to the way variable 'J' is used

I am receiving the following error in using parfor. Is there any way to use Parfor for here?
The parfor loop cannot be run due to the way variable 'J' is used
parfor xpop = 1:Xpop
Gxm = (X(xpop,M:Nvar)-0.5*ones(1,K)) * (X(xpop,M:Nvar)-0.5*ones(1,K))';
Cos = cos(X(xpop,1:M-1)*pi/2);
J(xpop,1) = prod(Cos)*(1+Gxm);
for nobj = 1:M-1
J(xpop,nobj+1) = (J(xpop,1)/prod(Cos(1,M-nobj:M-1)))...
* sin(X(xpop,M-nobj)*pi/2);
end
end*

 채택된 답변

Matt J
Matt J 2015년 3월 4일
편집: Matt J 2015년 3월 4일
There is, but it seems terribly unnecessary. Everything you are currently attempting to do with parfor is abundantly vectorizable,
xpop=1:Xpop;
Gxm=sum((X(xpop,M:Nvar)-.5).^2,2);
Cos = cos(X(xpop,1:M-1)*pi/2);
tmp1=prod(Cos,2).*(1+Gxm);
tmp2=tmp1./prod(Cos(1,M-nobj:M-1));
J(xpop,1:M)=[tmp1, bsxfun(@times,tmp2, sin(X(xpop,M-1:-1:1)*pi/2) )];

댓글 수: 3

still same error :(
Matt J
Matt J 2015년 3월 4일
편집: Matt J 2015년 3월 4일
No, there can't be any parfor error messages. There are no for loops or parfor loops in the code I gave you.
That's true, It doesn't have any errors. Thank you.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Parallel for-Loops (parfor)에 대해 자세히 알아보기

질문:

2015년 3월 4일

댓글:

2015년 3월 5일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by