Reorder a matrix relative to another

I have investigated all day the different ways to do this, and I have not been able to come up with a plan to achieve exactly what i need. Below are my sample matrices.

a=[5;20;50;30;10]

index=[1;2;3;4;5]

b=[10;50;5;20;50]

c=[44;22;11;88;55]

"a" and "index" are the proper order of the matrix. Matrix "b" is identical is size and shape, but the values are scrambled in order. I need a way to establish an order to move "b" to look like "a", and then apply that reordering pattern to "c". The only matrix i am interested in is the reordered "c"

In the end i want the new reordered matrix to be the following:

cReordered=[11;88;22;55;44]

I am looking for the most efficient way to do this.

I have used:

[bnew, ia, ib] = intersect(a, b, 'stable')

but it only reorders "b", by generating a "bnew". and this will match the pattern in "a", but that is all.

Any advice would be appreciated. thank you.

[Stephen23]

Are the values in a, b, and index unique? It seems that the vector b should actually be

b = [10;50;5;20;30];

(i.e. replacing the second 50 with 30), is this correct?

[Matthew]

Sorry i typed that wrong. Yes, the values in a and values in b will be identical, just those in b will be out of order.

b=[10;50;5;20,30]

Answer 1

[Stephen23]

Assuming that the values in both of a and b are unique, and that they each contain exactly the same values, then the vector b original question needs have the second 50 replaced with a 30, like this:

>> a = [5;20;50;30;10];
>> x = [1;2;3;4;5];
>> b = [10;50;5;20;30];
>> c = [44;22;11;88;55];

Then the solution is very easy using MATLAB's indexing ability:

>> [~,xx] = sort(a);
>> [~,yy] = sort(b);
>> d(xx) = c(yy)
d =
  11    88    22    55    44

Which matches the desired output [11;88;22;55;44]. Note that this requires that the values in a and b are unique!