I want plot theta as a function of z at t = time(nt) for all xi values but receive: Error using plot: Data cannot have more than 2 dimensions om line 140.

 채택된 답변

Torsten
Torsten 2022년 9월 14일

0 개 추천

%store your outputs for each xi
thetaxivalues(ixi,:,:) = theta(:,:);
vxivalues(ixi,:,:) = v(:,:);
What is ixi ? I guess, it's a single scalar, namely ixi = nxi from the last loop where ixi appears:
for ixi = 1:length(xivalues)
xi = xivalues(ixi);
end
So you don't store outputs for each xi.

댓글 수: 8

University Glasgow
University Glasgow 2022년 9월 14일
I actually wants the xi to take values from xivalues = linspace(-0.3, -0.1, nxi).
But your vector "theta" does not depend on xi.
So it makes no sense to set
thetaxivalues(1:nxi,:,:) = theta(:,:);
vxivalues(1:nxi,:,:) = v(:,:);
because every vector thetaxivalues and vxivalues will contain the same values for 1 <= ixi <= nxi.
University Glasgow
University Glasgow 2022년 9월 14일
You are right but what do you suggest then?
Torsten
Torsten 2022년 9월 14일
Your simulations must contain xi as a parameter and you must vary this parameter to get theta(xi,:,:) and v(xi,:,:).
University Glasgow
University Glasgow 2022년 9월 14일
Please, could you help me out.
Torsten
Torsten 2022년 9월 14일
편집: Torsten 2022년 9월 14일
How could I ?
I don't know anything about your model, and at the moment, I don't see a variable xi within the equations in lcode1 that could be varied.
University Glasgow
University Glasgow 2022년 9월 14일
If you cehck the discretised equations, I have xi in the v equation.
Please check, you will see: (xi/(2*h))*(theta(N-1)-theta(N-3));
Torsten
Torsten 2022년 9월 14일
편집: Torsten 2022년 9월 14일
Then call the solver in a loop over the elements of xi and write the results in a 3d v and theta array.
But that's really standard and I won't do that for you.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 MATLAB에 대해 자세히 알아보기

제품

릴리스

R2022a

질문:

2022년 9월 14일

편집:

2022년 9월 14일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by