Explicit solution can not be found using dsolve of second order differential equation

조회 수: 6 (최근 30일)
I have a second order differential equation of the form written below
I want to solve this differential equation using analytical method. For that I have written a code (see below)
%%%%%%%%%%%%%%%%
syms t y(t)
gamma=0.01;F=1;omega0=1;kappa=0.15;omega=0.15;
equation=diff(y,2)+2*gamma*diff(y)+omega0^2*(1+4*kappa*sin(2*omega*t))*y-2*F*sin(omega*t)==0;
Dy=diff(y);
conds = [y(0)==1,Dy(0)==0];
y = dsolve(equation,conds)
%%%%%%%%%%%%%%%%%
But whenever I run the code it shows explicit solution can not be found. I am new to MATLAB. Please help regarding this.
  댓글 수: 3
Abhik Saha
Abhik Saha 2022년 9월 12일
Hi @Torsten But still there are some cases I mean range of omegas like 0.47-0.50, 0.86-1.1 where I get the divergent solution
Torsten
Torsten 2022년 9월 12일
편집: Torsten 2022년 9월 12일
This question goes deeply into theoretical results about the boundedness of solutions of differential equations of the form
xdot = A(t)*x + b(t)
I'm not able to give you an answer whether the behaviour of ode45 is correct or due to numerical instabilities.
But since the behaviour of my solution curve under
looks very regular, my guess is that x can be unbounded for certain parameter constellations.
But the rule to decide if the solution will be bounded or unbounded from the parameter values is not possible for me.
Maybe Sam Chak can elaborate a little how he came up with the value of kappa <= 0.1469.

댓글을 달려면 로그인하십시오.

채택된 답변

Alan Stevens
Alan Stevens 2022년 9월 12일
Do you have a reason to believe there is an analytical solution to this?
It is simply solved numerically, as follows:
X0 = [1, 0];
tspan = [0 100];
[t, X] = ode45(@fn, tspan, X0);
plot(t,X(:,1)),grid
xlabel('t'), ylabel('x')
function dXdt = fn(t,X)
gamma=0.01;F=1;omega0=1;kappa=0.15;omega=0.15;
x = X(1); v = X(2);
dXdt = [v;
2*F*sin(omega*t)-omega0^2*(1+4*kappa*sin(2*omega*t))*x-2*gamma*v];
end

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Ordinary Differential Equations에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by