eval giving the wrong mathematical answer

조회 수: 7 (최근 30일)
Katie Doyle
Katie Doyle 2015년 2월 22일
편집: John D'Errico 2015년 2월 22일
I'm trying to write a script that I will use for Newton Rhapson approximation. I am testing as I go and I noticed that the eval command is returning the incorrect mathematical answer. I am testing it with x=2 with func=((2*x)*(log(x)))-1
Here is the code:
syms x;
func=input('Enter your function in terms of x: ');
f=@(x)(func);
z=diff(f(x));
f1=@(x)(z);
x0=input('Enter your initial value of x: ');
x=x0
s=char(f1);
y=subs(f1)
eval(y)
Upon entering x=2 and func=((2*x)*(log(x)))-1
The code redturns:
x =
2
y =
2*log(2) + 2
ans =
3.3863
The answer to 2*log(2)+2 should be 2.602
What am I doing wrong?

답변 (1개)

Roger Stafford
Roger Stafford 2015년 2월 22일
In matlab the 'log' function is considered to be the natural logarithm with base e, not 10. Therefore 3.3863 is the correct answer, not 2.602 .
  댓글 수: 1
John D'Errico
John D'Errico 2015년 2월 22일
편집: John D'Errico 2015년 2월 22일
And of course, if you really wanted a log to the base 10, use log10.
2*log10(2)+2
ans =
2.6021
Computers are so silly. They do what you tell them to do, instead of what you want them to do.

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