How to index the matrix only the first dimension of the rest

조회 수: 22 (최근 30일)
Xuze Liu
Xuze Liu 2022년 8월 31일
편집: Stephen23 2022년 9월 1일
For example, I have an matrix A=zeros(5,4,3)
And B=A(1,:,:)
Is there any way that I don't have to use the latter two ':'?
Something simple like B=A(1,?) that takes whatever from the second dimension onwards?

답변 (4개)

Bruno Luong
Bruno Luong 2022년 8월 31일
A = rand(2,3,4,5);
C=repmat({':'},1,ndims(A)-1);
% C=repmat({:},1,100); if you don't want to be depend on A
B = A(1,C{:});

Stephen23
Stephen23 2022년 9월 1일
This will be quite efficient because none of the data in memory is moved around, only the array header is accessed.
It also works for non-scalar X.
B = A(X,:);
S = size(A);
S(1) = size(B,1);
B = reshape(B,S);
  댓글 수: 1
Stephen23
Stephen23 2022년 9월 1일
편집: Stephen23 2022년 9월 1일
format compact
A = rand(5,4,3)
A =
A(:,:,1) = 0.9656 0.6497 0.2581 0.7417 0.5392 0.6739 0.5440 0.5115 0.7184 0.7770 0.1037 0.1437 0.0460 0.8504 0.7329 0.6772 0.5472 0.3287 0.3364 0.2696 A(:,:,2) = 0.0271 0.2944 0.1932 0.9287 0.1086 0.7801 0.5014 0.3357 0.5984 0.8400 0.6211 0.6933 0.0673 0.5048 0.7611 0.2261 0.9548 0.6398 0.8557 0.5052 A(:,:,3) = 0.8824 0.8974 0.9947 0.4210 0.0417 0.5307 0.0642 0.1385 0.7882 0.7552 0.9825 0.7442 0.5414 0.1979 0.8633 0.4881 0.7751 0.2920 0.6514 0.4335
X = 3;
B = A(X,:);
S = size(A);
S(1) = size(B,1);
B = reshape(B,S)
B =
B(:,:,1) = 0.7184 0.7770 0.1037 0.1437 B(:,:,2) = 0.5984 0.8400 0.6211 0.6933 B(:,:,3) = 0.7882 0.7552 0.9825 0.7442

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Walter Roberson
Walter Roberson 2022년 8월 31일
B=A(1,:);
However this will treat it like
temp = reshape(A, size(A, 1), []);
B = temp(1,:);
which would give you a 1 x 12 not a 1 x 4 x 3
  댓글 수: 2
Xuze Liu
Xuze Liu 2022년 9월 1일
Thanks. Any way I can avoid this "reshape" behaviour?
Bruno Luong
Bruno Luong 2022년 9월 1일
@Xuze Liu Walter explains the RHS of
B=A(1,:)
is like reshaping A with all the traling dimension grouped. You don't have to.

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Cris LaPierre
Cris LaPierre 2022년 8월 31일
It depends what you want the ouput dimensions to be. If you just want them in a vector, then you can just use a single colon.
A=rand(5,4,3)
A =
A(:,:,1) = 0.8151 0.1142 0.4037 0.5967 0.0920 0.2222 0.8144 0.6967 0.1565 0.9195 0.4080 0.7906 0.1481 0.9235 0.4610 0.4404 0.6894 0.7504 0.8451 0.0283 A(:,:,2) = 0.6298 0.0226 0.3653 0.7651 0.3858 0.3005 0.2023 0.8461 0.2826 0.2151 0.7336 0.5432 0.4013 0.0399 0.1543 0.5064 0.6406 0.9716 0.4377 0.8008 A(:,:,3) = 0.4181 0.4029 0.7620 0.6040 0.7262 0.1018 0.3144 0.6743 0.1473 0.6745 0.5357 0.1704 0.5709 0.9167 0.0451 0.7542 0.9045 0.3479 0.7617 0.6889
A(1,:)
ans = 1×12
0.8151 0.1142 0.4037 0.5967 0.6298 0.0226 0.3653 0.7651 0.4181 0.4029 0.7620 0.6040

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