Sum(sum()) with optimization variable
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I want to write the following equation as a constraint
and x is an optimization variable.
I managed to get to following formulation
Constraint2 = sum(sum(x,3),1) <= ones(1,nRess)
Now the problem is, that I do not know how to change the running boundries of the inner sum, to the above given form (so not all the elements of the dimension 3, but only starting from l=t-pt_jr to t, and also while l>0).
pt_jr is a 2D matrix.
I tried to write it with sum(sum()) as I read about vectorization and didn't want to generate too long working times wir for loops.
Thanks ahead for any ideas.
댓글 수: 1
Walter Roberson
2022년 8월 15일
What if you multiply x by a logical condition ? That would zero out some locations, and that would add nothing to the sum.
답변 (2개)
Jan
2022년 8월 15일
편집: Jan
2022년 8월 15일
Constraint2 = sum(x(:, :, (t - pt(j, r)):t), [1, 3]) <= 1;
댓글 수: 6
Jan
2022년 8월 18일
nTasks = 3;
nRess = 2;
maxPT = 50;
x = optimvar('x',nTasks,nRess,maxPT,'Type', 'integer','LowerBound',0,'UpperBound',1);
x is not an array we can sum over. While I was talking about an array, the introduction of optimvar() was out of my view. I have no idea, what the realtion between the question and this code is.
Bruno Luong
2022년 8월 15일
What about this:
L = reshape(1:size(x,3),1,1,[])
b = L >= t-pt_rj & L <= t;
Constraint2 = sum(sum(b.*x,3),1) <= ones(1,size(x,2))
댓글 수: 4
Bruno Luong
2022년 8월 18일
I'm lost, it sounds like you are stuck with how to transforming whatever the scheduling problem you want to solve in math formulation, and not transforming math into matlab.
If that is the case I won't be able to help you, for the simple reason is that I don't understand what you wrote in the description.
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