# Getting NaN while using the ratio of power and factorial

조회 수: 9 (최근 30일)
Yash Khandelwal 2022년 7월 13일
댓글: James Tursa 2022년 7월 13일
1
With the following piece of code, I get NaN
l=0;
lp=2;
d=200;
a2= ((-sqrt(d))^lp);
a3 =((-sqrt(d))^l);
sum1=0
for m=0:500
a1= ((2^m)*(d^m))/(factorial(m))
mul=a1*a2*a3;
sum1=sum1+mul;
end
Is there any way to modify the code to get rid of the issue?
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James Tursa 2022년 7월 13일
Cross posted on stackoverflow and answered there over 4 hours ago. If you had simply checked the answer there you could have saved yourself the trouble of posting here and getting essentially the same answer.

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### 답변 (4개)

Torsten 2022년 7월 13일
편집: Torsten 2022년 7월 13일
exp(400)*200 is quite large ...
format long
l=0;
lp=2;
d=200;
a2= ((-sqrt(d))^lp);
a3 =((-sqrt(d))^l);
a1 = 1.0;
sum1 = a1;
for m=0:500
a1 = a1* 2*d/(m+1);
sum1=sum1+a1;
end
sum1 = sum1*a2*a3
sum1 =
1.044293406962028e+176
exp(400)*200
ans =
1.044293937952829e+176
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Steven Lord 2022년 7월 13일
m = 500;
d = 200;
The numerator and denominator of your expression (for sufficiently large m) both overflow to inf. Dividing infinity by infinity results in a NaN.
numerator = 2^m*d^m
numerator = Inf
denominator = factorial(m)
denominator = Inf
x = numerator / denominator
x = NaN
One potential approach to avoid this is to avoid explicitly computing 2^m, d^m, or factorial(m).
numeratorVector = repmat(2*d, 1, m); % prod(numeratorVector) would effectively give numerator
denominatorVector = 1:m; % prod(denominatorVector) would effectively give denominator
xVector = numeratorVector./denominatorVector;
format longg
x2 = prod(xVector)
x2 =
8.78187252741829e+166
Let's check symbolically.
numeratorSymbolic = sym(2*d)^m;
vpa(numeratorSymbolic) % Pretty big
ans =
1.07150860718626732094842504906e+1301
denominatorSymbolic = factorial(sym(m));
vpa(denominatorSymbolic) % Also pretty big
ans =
1.220136825991110068701238785423e+1134
x3 = vpa(numeratorSymbolic/denominatorSymbolic) % Big but not quite as big as above
x3 =
8.7818725274182843596325298923868e+166
You could be a little more sophisticated / clever if you wanted (preemptively cancelling out factors of 2 in numeratorVector by dividing even values in denominatorVector by 2.) Or you could keep track of x for each value of m then figure out what you need to multiply it by to get x for the next value of m.
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Benjamin Thompson 2022년 7월 13일
The factorial function output increases very fast as input increases. See "doc factorial" for details. The output is "inf" for input of 171 or larger.
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Steven Lord 2022년 7월 13일
But 400^m overflows for m > 118 so this whole expression becomes infinite or undefined beyond that point.
d = 200;
(2*d)^118
ans = 1.1043e+307
(2*d)^119
ans = Inf

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Vijeta Singh Yadav 2022년 7월 13일
Data overflow and underflow problem exists in the code
visit this link for avoid data overflow and underflow problems.

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