# reversing the digits into a string

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cgo 2022년 7월 10일
댓글: John D'Errico 2022년 7월 10일
I have a list of numbers.
l1 = randi([0,9],[1,10]);
I want to make this into a string without the spaces and then reverse the digits.

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### 답변 (1개)

Kshittiz Bhardwaj 2022년 7월 10일
Hello cgo,
I understand that you want to convert your list into a string and then reverse it.
S = l1(:)';
This will convert your 2*2 array into a 1*4 array
str = char( S ) converts the input list to a char array
rev = reverse( str ) reverses the order of the characters in str .
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cgo 2022년 7월 10일
sorry, didnt take away the spaces in between characters
John D'Errico 2022년 7월 10일
Sorry, but this part is wrong:
S = l1(:)';
since that makes it into a coumn vector. And there is no reason to do so. l1 is a ROW VECTOR ALREADY. It is not a 2x2 array of numbers. You seem to have misunderstood what randi does.
l1 = randi([0,9],[1,10])
l1 = 1×10
5 6 0 6 3 3 9 7 9 1
Now, how do you convert those digits into characters? The use of char is also wrong, but subtly so. You need to convert them into their ascii representation as digits first, if you would use char. Adding '0' does that.
S = char(l1 + '0')
S = '5606339791'
Finally, you can use either flip or reverse to do the order swapping operation.
reverse(S)
ans = '1979336065'
flip(S)
ans = '1979336065'

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