how to deal with an error with exportgraphics

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alpedhuez
alpedhuez 2022년 7월 9일
댓글: alpedhuez 2022년 7월 9일
I write something like
pl=plot(x,y)
hold on
plot(x,z)
hold off
legend('test')
(some other code for axis information)
exportgraphics(pl, 'test.tif', 'ContentType','vector')
Then got an error message
"Error using exportgraphics
The value of 'handle' is invalid. Specified handle is not valid for export."
What shall I do?

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Image Analyst
Image Analyst 2022년 7월 9일
Your pl is a handle to the curve that plot drew. It's not the handle to the entire graph. The last axes you drew to is called gca, so try
exportgraphics(gca, 'test.tif', 'ContentType','vector')

추가 답변 (1개)

Jan
Jan 2022년 7월 9일
편집: Jan 2022년 7월 9일
As the documentation says, the handle must be:
axes | figure | standalone visualization | tiled chart layout | ...
plot replies a line-object. Solution:
AxesH = axes;
pl=plot(x,y)
...
exportgraphics(AxesH, 'test.tif', 'ContentType','vector')
If you get an error message, read it carefully and compare it with the details given in the documentation:
doc exportgraphics
"The value of 'handle' is invalid" means, that the 1st input is the problem. So check, what is expected as 1st input.

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