i have matlab 2014b and when i came to get taylor expansion of some functions by writting taylor(sin(x),5,0) the matlab gives error knowing that all other functions works properly thanks in advance

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Star Strider
Star Strider 2015년 2월 5일

0 개 추천

If you want to do a 5th-order Taylor series around an expansion point of 0 in R2014b, this works:
syms x
TSsin5 = taylor(sin(x), x, 'ExpansionPoint',0, 'Order',5)
and produces:
TSsin5 =
- x^3/6 + x
James Tursa
James Tursa 2015년 2월 5일
편집: James Tursa 2015년 2월 5일

0 개 추천

It is complaining about the 5 and 0 arguments, which don't match the expected syntax for calling the taylor function. Is something like this what you are trying to do?
>> syms x
>> taylor(sin(x))
ans =
x^5/120 - x^3/6 + x
>> taylor(sin(x),'Order',10)
ans =
x^9/362880 - x^7/5040 + x^5/120 - x^3/6 + x

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2015년 2월 5일

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2015년 2월 5일

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