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adding variable in the name of table for while loop

조회 수: 1 (최근 30일)
Sunghwan Kim
Sunghwan Kim 2022년 6월 29일
댓글: Sunghwan Kim 2022년 6월 29일
I need to do the following job
Alq_4_t.Properties.VariableNames{1} = 'mz';
...
Alq_36_t.Properties.VariableNames{1} = 'mz';
So, I made a loop like this.
"i=4;
while i<37
Alq_i_t.Properties.VariableNames{1} = 'mz';
i=i+1;
end "
I run this script and there was no error. However, the variable names were not changed at all. Can anyone let me know why? Thanks in advance.
  댓글 수: 1
Stephen23
Stephen23 2022년 6월 29일
편집: Stephen23 2022년 6월 29일
"Can anyone let me know why?"
Because a literal "i" in the variable name is not automagically updated using the value of some variable that happens to be named "i". Imagine the chaos that would ensue if that were the case.
Forcing pseudo-indices into the variable names forces you into writing slow, complex, inefficient, obfsucated, buggy code when you try to access your data in a loop:
In contrast, when using actual indices your code will be simpler and much more efficient. You should use indexing.
You have not told us the most important information: how did you get all of those variables into the workspace? I doubt that you named them all by hand...

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채택된 답변

Keshav
Keshav 2022년 6월 29일
편집: Keshav 2022년 6월 29일
you can not use i as a variable inside Alq_i_t variable name. and instead of making 36 different variable you can make an array of size of 36 by using below code.
i=1;
while i<37
Alq_t{i}.Properties.VariableNames{1} = 'mz';
i=i+1;
end

추가 답변 (1개)

KSSV
KSSV 2022년 6월 29일
i=4;
while i<37
Alq_i_t.Properties.VariableNames{i} = 'mz';
i=i+1;
end

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