The sc value in the equation B should be function of x
sc(x) that depends on range x= 0:0.01:10

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Garmit Pant
Garmit Pant 2022년 6월 28일
Can you please elaborate as to what exactly is the problem that you are facing?
Anfal AlShehhi
Anfal AlShehhi 2022년 6월 28일
I want to write the varibale sc in Equation B as a function of x
B(x) = rhoref/ rhot * x^2/ xref^2 * exp ( -2 * atm * xref)^10^-er/10 / T * sc(x)
x is the range from 0 to 10
Then define
sc = @(x) ... % whatever the definition is.
But since you have set the values of x previously you could just set
sc = ... % directly in terms of x

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답변 (1개)

Alan Stevens
Alan Stevens 2022년 6월 28일
편집: Alan Stevens 2022년 6월 28일

0 개 추천

  1. You need to define sc before using it in B.
  2. In B you have ...1000/dref*dref.... This just means the dref va;lues cancel each other out. Did you mean ...1000/(dref*dref)...?
PS Upload the actual code, niot an image. Use the > symbol above.

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Anfal AlShehhi
Anfal AlShehhi 2022년 6월 28일
Yes exactly. 1000/(dref*dref)
Anfal AlShehhi
Anfal AlShehhi 2022년 6월 28일
편집: Anfal AlShehhi 2022년 6월 28일
clc; clear all;
% Defined values
atm=0.17 % km-1
xt=2.3; % target (x) in m
yt=2.3; % target (y) in m
p=50/100; % percent target
vis=23; %Visibility in km target
er=26; % LRF
dref=500; % LRF in m
pref=85/100; % LRF
vis2=23; % LRF Visbility
T=90/100; % LRF
% Range
x=0:0.01:10; % in km
A= exp(-2*atm.*x) % Attenuation func
sc =
B= ((pref/p)*((x.*x)*1000/dref*dref))*(((exp((-2*atm*dref/1000))*10^(-er/10)))/(T*sc)) % Sensi func
% plotting
figure
plot(A,x.*1000,'-b')
hold on
plot(B/1000,x.*1000,'-r')
grid on
xlabel("Range in km")
ylabel("Distance in km")
title("Range Preformance")
legend('Atmospheric Attenuation','Sensitivity')
hold off
Alan Stevens
Alan Stevens 2022년 6월 28일
You need to define sc.
If you don't know what sc is, how is Matlab to know?

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