passing a function to another function
조회 수: 2 (최근 30일)
이전 댓글 표시
Hi
I am trying to pass the following function "haar" to the function integral. I am getting the following error. plz suggest. thanks
function val = haar(x)
if ((0<=x) && (x<0.5))
val=1;
elseif ((0.5<= x) && (x < 1))
val =-1;
else
val =0;
end
end
EDU>> fhnadle=@haar;
EDU>> integral(fhnadle,0,1)
Operands to the || and && operators must be convertible to logical scalar values
댓글 수: 0
채택된 답변
Sean de Wolski
2015년 2월 3일
편집: Sean de Wolski
2015년 2월 3일
integral calls the function with a vector x, you're expecting x to be a scalar in your haar function. E.g:
>> [1 2 3] && 1
The easiest thing for you to do is to modify haar to use logical indexing on val:
function val = haar(x)
val = zeros(size(x)); % assume zero
val(0<=x & x<0.5) = 1; % set ones
val(0.5<=x & x<1) = -1; % set -1s
end
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Discrete Multiresolution Analysis에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!