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Why am I getting syntax

조회 수: 1 (최근 30일)
Kausalya Devi Subramaniam
Kausalya Devi Subramaniam 2022년 6월 13일
답변: Benjamin Thompson 2022년 6월 13일
dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
I dont know where i go wrong. I keep on getting syntax parentheses error.

답변 (1개)

Benjamin Thompson
Benjamin Thompson 2022년 6월 13일
Missing two closing parenthesis it would appear. Is MATLAB suggestion not correct? You might do better breaking this up into multiple lines using the ... operator notation for easier readability.
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
Did you mean:
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))+(db.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))).^2)));

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