Can I speed up an ismember operation?

조회 수: 7 (최근 30일)
Christopher
Christopher 2015년 1월 31일
댓글: Matt J 2015년 2월 1일
I have a list of 100 random numbers 1-10:
numpoints = 100;
gridnum = 10;
grid_ind = randi(gridnum,[numpoints 1]); % 100 points in 10 random cells
and each of the 10 possible values has a corresponding list (of random length) of values, which are indexes to grid_ind:
for i=1:gridnum
neighbgrids{i} = randi(numpoints,[randi(5) 1]);
end
So far, so good. Now, I need to find the indexes for all elements in grid_ind which have the same values as in each cell list in neighbgrids. So I use:
for i=1:numpoints
neighblist{i} = find(ismember(grid_ind,neighbgrids{grid_ind(i)}));
end
But this turns out to be very slow. Is there a faster way to do this part?
  댓글 수: 5
Matt J
Matt J 2015년 2월 1일
편집: Matt J 2015년 2월 1일
@Christopher,
Your code takes .006 sec to run on my machine. What speed were you hoping for?
If these are just example numbers, what are the actual typical values of numpoints and gridnum? Is numpoints always much larger than gridnum?
Christopher
Christopher 2015년 2월 1일
gridnum is ideally going to be around 100-1000 and numpoints will always be around 2-25 times that number.

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Matt J
Matt J 2015년 2월 1일
편집: Matt J 2015년 2월 1일
This should speed things up.
for i=1:gridnum
neighblist{i} = find(ismember(grid_ind,neighbgrids{i}));
end
neighblist=neighblist(grid_ind);
I see a 10x speed-up over your originally posted example.
  댓글 수: 2
Christopher
Christopher 2015년 2월 1일
Thanks! This gives me about a 5x speedup the way it is implemented in my code.
Hopefully I can think of a way to avoid ismember all together, in the future, as I was hoping for significantly more speedup.
Matt J
Matt J 2015년 2월 1일
It seems inefficient to be using find(). The output of ismember is enough to index into grid_inds and then you could maintain neighblist as a matrix instead of a cell, which is more efficient:
neighblist=zeros(gridnum,numpoints);
for i=1:gridnum
neighblist(i,:) = ismember(grid_ind,neighbgrids{i});
end

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