fprintf within a for / if environment with crazy behaviour
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Using fprintf in a for / if environment (fileID = correct.XP0000020_0026.dat):
if ProfilKonst == 'X'
if x(i) == koordinate(1)
fprintf(fileID,'%.2f %.2f %.2f\n',[x(i) y(i) z(i)]);
the file 'correct.XP0000020_0026.dat' is empty, and the output on the console is:
correct.XP0000020_0026.datcorrect.XP0000020_0026.datcorrect.XP0000020_0026.datcorrect.XP0000020_0026.dat..........and so on
But when I use
fprintf('%.2f %.2f %.2f\n',[x(i) y(i) z(i)]);
everything is fine.
The file is opened with fopen(fileID,'wt'). I also tried to move fprintf in a function, but with the same result...
What is wrong? Thanks a lot.
Stephen23 2022년 6월 9일
편집: Stephen23 2022년 6월 9일
The file is opened with fopen(fileID,'wt')"
Perhaps, but in any case, you did not provide the file identifier to FPRINTF.
"What is wrong?"
You did not provide a valid file identifier to FPRINTF. You are doing this:
fileID = 'correct.XP0000020_0026.dat';
fprintf(fileID,'%.2f %.2f %.2f\n',[x(i) y(i) z(i)])
% ^^^^^^ prints the filename
% ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ these are ignored
whereas what you need to do is get the identifier from FOPEN and use that:
fid = fopen(correct.XP0000020_0026.dat','wt');
fprintf(fid,'%.2f %.2f %.2f\n',[x(i) y(i) z(i)])