string and isinteger

조회 수: 18 (최근 30일)
Leor Greenberger
Leor Greenberger 2011년 10월 3일
Hi. I created a GUIDE UI and I am trying to determine whether an input into an editable textbox is an integer.
If I do:
[I,OK] = str2num(get(handles.no_ADC,'String'));
disp(isinteger(I))
The output is 0 (or false), because str2num converts strings into type floating. I thought about doing
isinteger(uint8(I))
but that is useless too because it would just convert an I=3.2 to 3 and return true, which is not what I want.
Is my only option to do
strfind(num2str(I),'.')
since this will tell me if there is a decimal point in I, which means its not an integer?

채택된 답변

Fangjun Jiang
Fangjun Jiang 2011년 10월 3일
try this
a=[1 1.1 -1 -1.2]
TF=a==round(a)
  댓글 수: 1
Jan
Jan 2011년 10월 3일
+1: Exactly. Exception: round(Inf)==Inf.
ISINTEGER checks the *type* of the variable, not the *value*.

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추가 답변 (2개)

Jan
Jan 2011년 10월 3일
Note that STR2NUM accepts characters also, because it uses EVAL to computer the reply:
str2num('sin(pi)') % 1.2246e-016
and do not try this:
str2num('!format C:')
Therefore it is recommended to avoid STR2NUM to convert inputs from the user-land if it is possible. SSCANF is safe. The following converts the input to an integer automatically:
Num = round(sscanf(get(handles.no_ADC,'String'), '%f', 1));
if isempty(Num)
warning...
else
set(handles.no_ADC, 'String', sprintf('%d', Num));
end
E.g. "1.0" is read as [1] and converted to "1".
  댓글 수: 3
Walter Roberson
Walter Roberson 2011년 10월 3일
It *is* in the documentation, and is why mlint flags str2num and recommends using str2double instead.
Jan
Jan 2011년 10월 3일
@Daniel: I think, your comment has the same level of humor as my example. "!format C:" looks dangerous, but it does not work since WindowsNT anymore. In addition, users typing such commands cannot complain, because they are the most unsafe part in the system.
The real problem is more using "O" or "l" (upper-case oh, lower-case el) instead of "0" or "1" (zero, one). Then num2str can evaluate a function or local variable instead of showing an error. Then possible side-effects are more likely than extremly stupid and/or bold users.
A realistic scenario is a GUI which is shipped to the customers in compiled form. Then applying EVAL to user inputs can reveal internal details by injecting code, e.g. by typing "whos" instead of a number. Equivalent tricks are used to hack web-based databases as internet-shops etc, ask Google for "sql injection" to learn more.
Although I assume the the OP does not use the input to contact a database, which contains critical information, it is a good idea to mention security risks in this public forum.

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Daniel Shub
Daniel Shub 2011년 10월 3일
validateattributes(I, {'numeric'}, {'integer'})
You may need to wrap it in a try/catch block since validateattributes throws an error if the check doesn't pass.

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