break from a nested for loop

hi, i have the below matrix , i want each row to have only on value equal to '1' , so when searching if it find a one it will take it and make the rest values of the row equal to zero . i write the bellow code , i need to break the second loop when the if condtion is true , any one can help?

  
D=[  1     1     1     1     1
     1     1     1     1     1
     0     0     0     0     0
     0     1     0     0     0
     1     1     0     1     1
     0     0     1     0     0
     0     0     0     0     0
     0     0     1     0     0
     1     0     0     1     1
     0     0     0     0     0]

D = 10×5

1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0

N=10;
M=5;
for n=1:N
              for m=1:M
                 if D(n,m)==1 
                     Dn(n,m)=1;
                     Dn(n,m+1:end)=0;
                     
                 else Dn(n,m)=0;
                 end
              end 
         end 
          Dn

Dn = 10×5

1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0

Answer 1

[Image Analyst]

Try using a flag

abort = false;
for n = 1 : N
    for m = 1 : M
        if conditionForBreaking
            abort = true; % Set flag
            break;  % Exit inner loop.
        end
    end
    if abort
        break % exit outer loop.
    end
end

[kurdistan mohsin]

thank you

[Image Analyst]

Why not simply use find instead of all that complicated stuff (abort flag and nested loops):

D=[  1     1     1     1     1
    1     1     1     1     1
    0     0     0     0     0
    0     1     0     0     0
    1     1     0     1     1
    0     0     1     0     0
    0     0     0     0     0
    0     0     1     0     0
    1     0     0     1     1
    0     0     0     0     0];
[rows, columns] = size(D);
for row = 1 : rows
    indexOfFirst1 = find(D(row,:) == 1, 1, 'first');
    if ~isempty(indexOfFirst1)
        % If there is a one in the row, make all elements
        % in the row zero after that one.
        D(row, indexOfFirst1+1:end) = 0;
    end
end
D

D = 10×5

1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0

[kurdistan mohsin]

it works too, thanks again

Answer 2

[Mitch Lautigar]

https://www.mathworks.com/help/matlab/ref/continue.html

Using Matlabs "continue" command should do what you need.

[kurdistan mohsin]

thank you