Check for incorrect argument data type or missing argument in call to function 'isfinite'.

c=8;

x=9;

y=10;

f=@(x,y)(f1(x,y,c)+f3(x,y,c));

ff=@(x,y)f2(x,y,c);

eqs=@(x,y)[f(x,y),ff(x,y)];

sols=[0,0];

sols=fsolve(@(x,y)eqs,[2,1]);

function f=f1(x,y,c)

f=x*y-c;

end

function ff=f2(x,y,c)

ff=1-c*x/y;

end

function fff=f3(x,y,c)

fff=1;

end

Trying to learn how to use fsolve and stuck on this. Any help?

Answer 1

[Star Strider]

Change ‘eqs’ to be a funciton one one argument, and it works —

c=8;
x=9;
y=10;
f=@(x,y)(f1(x,y,c)+f3(x,y,c));
ff=@(x,y)f2(x,y,c);
eqs=@(b)[f(b(1),b(2)),ff(b(1),b(2))];                   % <— Needs To Be Parameterised With One Vector Argument
sols=[0,0];
sols=fsolve(eqs,[2,1])

Equation solved.

fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.

sols = 1×2

0.9354 7.4833

function f=f1(x,y,c)
   f=x*y-c;
end
function ff=f2(x,y,c)
   ff=1-c*x/y;
end
function fff=f3(x,y,c)
   fff=1;
end

.