Change for loop to while loop.

I need to convert this code from the for loop to while loop but when I tried to do so, it always comes out as error. Please help :(

n = input ("Input a number: ");
fprintf("\nOdd number: ");
for i = 1:2:n
    fprintf("%d ",i);
end
fprintf("\nEven number: ");
for i = 2:2:n
    fprintf("%d ",i);
end
fprintf("\nSum of Even numbers: ");
sum = 0;
for i = 2:2:n 
    sum = sum + i;
end
fprintf("%d",sum);
prod = 1;
fprintf("\nProduct of Odd numbers: ");
for i = 1:2:n
    prod = prod*i;
end
fprintf("%d",prod);

[DGM]

Why? It would only require more code and introduce more opportunities for bugs. If your loop has a known number of iterations, use a for loop.

[Cha Rot]

It is the one required by our teacher as he wanted us to differentiate the for loop and while loop and prove that it will produce the same output.

The output should be like this. This is a sample output.

Input a number: 15

Odd Number: 1 3 5 7 9 11 13 15

Even Number: 2 4 6 8 10 12 14

Sum of Even Numbers: 56

Product of Odd Numbers: 2027025

[Dyuman Joshi]

What have you tried? What error does it show?

[Cha Rot]

This is the code I tried.

n = input ("Input an integer: ");

fprintf('Odd numbers: ')

x = 1;

while x < n

x = 1:2:n;

fprintf(' %d',x)

break

end

fprintf('\nEven numbers:')

y = 0;

while y < n

y = 2:2:n;

fprintf(' %d',y)

break

end

fprintf('\nSum of even numbers:')

y = 0;

even_sum = 0;

while y < n

y = 2:2:n;

even_sum = even_sum + y;

fprintf(' %d', even_sum)

break

end

fprintf('\nProduct of odd numbers: ')

x = 1;

while x < n

x = 1:2:n;

odd_product = odd_product * x

fprintf(' %d',x)

break

end

But the last 2 parts, the sum of even numbers and product of odd numbers always produces the wrong outputs.

[DGM]

Again:

fprintf('\nProduct of odd numbers: ')
x = 1;
odd_product = 1; % need to initialize to something nonzero
while x <= n % less than or equal to
    odd_product = odd_product * x;
    fprintf(' %d',odd_product) % not x
    x = x+2; % increment x
end

Answer 1

[Dyuman Joshi]

%n = input ("Input an integer: ");
n=11;
fprintf('Odd numbers: ')

Odd numbers: 

x=1;o=1;
while x<=n
    fprintf(' %d',x)
    o=o*x;
    x=x+2;
end

 1 3 5 7 9 11

fprintf('\nEven numbers:')

Even numbers:

y=0;e=0;
while y<=n
    fprintf(' %d',y)
    e=e+y;
    y=y+2;
end

 0 2 4 6 8 10

fprintf('\nSum of even numbers: %d', e)

Sum of even numbers: 30

fprintf('\nProduct of odd numbers: %d', o)

Product of odd numbers: 10395

Answer 2

[DGM]

If you want to make things more complicated, you can:

n = 5; %input ("Input a number: ");

fprintf("\nOdd number: ");
i = 1;
while i <= n
    fprintf("%d ",i);
    i = i+2;
end
% and so on