Setting an element of an array to zero based on the values of a vector

Given a 2D array with elements a(i,j), if either i or j matches any element in another vector, how do you set the value for that a(i,j) = 0?

So, for example, given A = magic(5), how do you set to 0 any element of A given a vector B = [1 2 5 8] if 1, 2, 5, or 8 is an entry in A?

Here, I want to obtain:

A =

    17    24     0     0    15
    23     0     7    14    16
     4     6    13    20    22
    10    12    19    21     3
    11    18    25     0     9

Answer 1

[Matt J]

A(B,B)=0;

[L'O.G.]

No, that sets (for example) A(1,1) = 0 despite that A(1,1) originally is 17, which is a number not found in the vector B.

[Matt J]

Your question specifies that a(i,j) should be set to 0 "if either i or j matches any element in another vector". Since 1 belongs to the other vector B, your requeirement implies that a(1,:) and a(:,1) should be set to 0.

[L'O.G.]

I suppose I didn't put it well. I meant in this case, A(1,1) = 17, but 17 is not in B and therefore A(1,1) should be left as it is.

[Matt J]

A = magic(5),

A = 5×5

17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9

B = [1 2 5 8]; 

A( ismember(A,B) )=0

A = 5×5

17 24 0 0 15 23 0 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 0 9