divide function in trainbr train function

hello I have made a feedforward neural network. when I set the net.trainFcn to trainbr, and the divide function to divideblock or dividerand with train/val/test ratio of 70/0/30 after training the network, the devideFcn in the training result is set to dividetrain and all of the input data is used for training, and tr.testInd is empty what am I doing wrong? thanks in advance.

 채택된 답변

Greg Heath
Greg Heath 2015년 1월 6일

0 개 추천

The TRAINBR code covering indexing and ratios is BUGGY. I couldn't figure it out when I looked at it back in June 2013.
Now that I'm older, I might have better luck.
1. Complain to MATLAB, directly, with specific, repeatable, examples on MATLAB data
help nndata
doc nndata
2. Experiment some more to see if you can impose something other than the 80/0/20 default.
3. Another possibility is to use TRAIN with msereg
Hope this helps.
Thank you for formally accepting my answer
Greg
P.S. Please report any findings

댓글 수: 1

erte
erte 2015년 1월 6일
I tried to make custom divide function to divide data manually before training. but thank you so much.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Sequence and Numeric Feature Data Workflows에 대해 자세히 알아보기

질문:

2015년 1월 5일

댓글:

2015년 1월 6일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by