Separate arrays within loop using indexing?

I have matricies for start and stop time of system cycle. How can i iterate this over a raw dataset so that each loop produces a new matirix containing the points from start(i) to stop(i)?

start and stop will have equal elements but may have numel 1-20

if start has 5 elements loop will produce data.1-data.5

What im looking for:

ex start=[1,8]; stop=[7,11]

data=[2,2,2,3,3,4,4,2,3,4,4,2]

ans=

data.1=[2,2,2,3,3,4,4]

data.2=[2,3,4,4]

have tried:

for k=1:numel(start)
    seperated_data(k)=data(start(k):stop(k))
end

Answer 1

[DGM]

You should just be able to use a cell array.

start = [1,8];
stop = [7,11];

data = [2,2,2,3,3,4,4,2,3,4,4,2];

% same thing, but with a cell array
seperated_data = cell(numel(start),1);
for k = 1:numel(start)
    seperated_data{k}=data(start(k):stop(k));
end

% show the contents of the output
celldisp(seperated_data)

 
seperated_data{1} =
 
     2     2     2     3     3     4     4

 
 
seperated_data{2} =
 
     2     3     4     4

 

[Nicholas Kavouris]

Worked like a charm! Thank you.

Answer 2

[Walter Roberson]

start = [1,8];
stop = [7,11];
data = [2,2,2,3,3,4,4,2,3,4,4,2];
seperated_data = arrayfun(@(B,E) data(B:E), start, stop, 'uniform', 0)

seperated_data = 1×2 cell array
    {[2 2 2 3 3 4 4]}    {[2 3 4 4]}