# how to plot compelex function

조회 수: 20 (최근 30일)
Aisha Mohamed . 2022년 3월 25일
편집: Torsten . 2022년 3월 25일
I want to add some information that make this question more clear
1- I use p=[(0.9-0.124i) (0.4243 + 0.0017i) (0.10 + 0.3i)]; and as t change time = 0:0.01:2*pi (polynomial in z inthe second degree) f(z) = (0.10 + 0.3i) + (0.4243 + 0.0017i)z + (0.9-0.124i)z^2
the coefficients of p will cange with time by using this relation | f(t)> =exp(i t H)|f(0)>,for some H (given) and |f(0)> are the coefficients of p at t=o, and at every time I have new coefficients | f(t)> and plot the function p.
2- the function f(1/z) at every time must use the complex conjugate of the coeffecients of p (multiply in some constants)which also change with time t by the same way that coefficients of p do(in this case f(1/z) is the function of 1/z in the third degree) f(1/z) = (0.10 0.3i)z^-1 + (0.2121 0.0008i)z^−2 + (0.9 + 0.001i)z^−3.
How can I plot the two function in this case?
When I am trying to plot f(z) and f(1/z) I got paths in complex plane (not serface). and I am not sure that plots are correct.
I will appreciate any help
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Torsten 2022년 3월 25일
편집: Torsten 님. 2022년 3월 25일
So f will depend on t and on z :
f(z,t) = exp(i*t*H) * p * [z.^2;z;1]
?
And
g(z,t) = exp(i*t*H) * conj(p) * [z.^3;z.^2;z]
?
And how do you want to plot f(z,t) and g(1/z,t) ?
If the above form of the functions is true, f and g are functions from C x R -> C.
I don't understand how you want to plot them.

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