Extract info using regular expression matching

Hello together,

I was trying to do some regurlare expression, I am getting correct output which i was expecting. can you please help me

myinp = {['getval' ('MYINFO\ECE1') '==19 & (getval(' 'MYDataCode\CSE' ') >= 4) & (getval(' 'MYCHANGE\DEPT' ') < 6'] };
[a,b]=regexp(myinp,'([^"])','tokens');

%expected output should be like

a{1,1} = getval('MYINFO\ECE1')
a{1,2} = getval('MYDataCode\CSE')
a{1,3} = getval('MYCHANGE\DEPT')

[Rik]

myinp = {['getval' ('MYINFO\ECE1') '==19 & (getval(' 'MYDataCode\CSE' ') >= 4) & (getval(' 'MYCHANGE\DEPT' ') < 6'] }

myinp = 1×1 cell array
    {'getvalMYINFO\ECE1==19 & (getval(MYDataCode\CSE) >= 4) & (getval(MYCHANGE\DEPT) < 6'}

There are no quotes anywhere in this cellstr. Or is the actual input different from what you show us here?

[Murugan C]

this is my input

myinp = {['getval(' '''MYINFO\ECE1''' ')' '==19 & (getval(' '''MYDataCode\CSE''' ') >= 4) & (getval(' '''MYCHANGE\DEPT''' ') < 6)'] }

myinp = 1×1 cell array
    {'getval('MYINFO\ECE1')==19 & (getval('MYDataCode\CSE') >= 4) & (getval('MYCHANGE\DEPT') < 6)'}

[Stephen23]

Your text does not have any double quote characters, that regular expression will match everything.

What is the purpose of the superfluous scalar cell array?

Answer 1

[Rik]

Maybe this is what you need?

myinp = {['getval(' '''MYINFO\ECE1''' ')' '==19 & (getval(' '''MYDataCode\CSE''' ') >= 4) & (getval(' '''MYCHANGE\DEPT''' ') < 6)'] };
[a,b]=regexp(myinp{1},'getval\(''([^'']*)''\)','match')

a = 1×3 cell array
    {'getval('MYINFO\ECE1')'}    {'getval('MYDataCode\CSE')'}    {'getval('MYCHANGE\DEPT')'}

b = 1×3

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