Loop through same procedure for different inputs.

Hi! I am getting stuck on something i believe is quite trivial, i have written out the code in full below that i am using. I am trying to combine the long code into a singular loop that filters through the three different time periods (5s,10s, 20s) giving the three seperate results as an output. Any help is greatly appreciated!

cnt = 15;   % centre point (s)
fqn = 200;  % scale factor (Hz)

t = 5;                    % time period (s)
LBD = fqn.*(cnt-(t./2));  % define lower boundary
UBD = fqn.*(cnt+(t./2));  % define upper boundary
c5_5s = c5(LBD:UBD,3);    % isolate values within the boundary conditions

UM5S = mean(c5_5s);                       % calculate time-avg mean
disp(['t_5s = ',num2str(UM5S), ' m/s'])   % display result

t = 10;                  % time period (s)
LBD = fqn.*(cnt-(t./2));  % define lower boundary
UBD = fqn.*(cnt+(t./2));  % define upper boundary
c5_10s = c5(LBD:UBD,3);   % isolate values within the boundary conditions

UM10S = mean(c5_10s);                      % calculate time-avg mean
disp(['t_10s = ',num2str(UM10S), ' m/s'])  % display result

t = 20;                   % time period (s)
LBD = fqn.*(cnt-(t./2));  % define lower boundary
UBD = fqn.*(cnt+(t./2));  % define upper boundary
c5_20s = c5(LBD:UBD,3);   % isolate values within the boundary conditions 

UM20S = mean(c5_20s);                     % calculate time-avg mean
disp(['t_20s = ',num2str(UM20S), ' m/s']) % display result

Answer 1

[Jan]

cnt = 15;   % centre point (s)
fqn = 200;  % scale factor (Hz)

for t = [5, 10, 20]           % time period (s)
   LBD  = fqn.*(cnt-(t./2));  % define lower boundary
   UBD  = fqn.*(cnt+(t./2));  % define upper boundary
   ct   = c5(LBD:UBD,3);      % isolate values within the boundary conditions
   UMtS = mean(ct);                       % calculate time-avg mean
   fprintf('t_%is = %f m/s', t, UMtS);    % display result
end

[Ben Bawtree]

Thank you!