How to do it more efficiently?
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Hi,
In my script, this piece of code is taking about 70% of processing time.
The idea is to create uniform timestamp, it searches the time array and compare it with the Tsynced. if there is no similar entry, the other parameters to NaN.
Is there anyway to change the script below without using find function? Even better if no for-loop is required.
Code:
for ix = 1:length(time_synced)
[r,~,~] = find(cCells(:,1)==time_synced(ix),1,'first');
if isempty(r)
curArr(ix,:) = NaN;
else
curArr(ix,:) = cCells(r,:);
end
end
Thanks.
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채택된 답변
Roger Stafford
2014년 12월 23일
See if this is faster:
[t,ic] = ismember(time_synced,cCells(:,1));
curArr(t) = cCells(ic);
curArr(~t) = NaN;
Note: This assumes that 'time_synced' and 'curArr' are vectors of the same length.
추가 답변 (1개)
Andrei Bobrov
2014년 12월 23일
[l0,ii] = ismember(time_synced,cCells(:,1));
out = nan(numel(time_synced),size(cCells,2));
out(l0,:) = cCells(ii(l0),:);
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