How to apply dec2bin to char array?

I have a data as char

a ='1234567';

dec2bin(a) gives

6×6 char array

'110001'

'110010'

'110011'

'110100'

'110101'

'110110'

but I want the result like dec2bin(123456)= '11110001001000000'

How to apply dec2bin to a char value to get a sinle out put ?

[Stephen23]

a ='1234567';
b = dec2bin(str2double(a))

b = '100101101011010000111'

Answer 1

[Stephen23]

"there is a problem with more digits in a like a='12362534624362643243256346523462'..."

The DOUBLE numeric class can only store 15 or so decimal digits or precision, it cannot store that entire number that you have shown without some loss of information. So converting to a scalar numeric using STR2NUM, STR2DOUBLE, SSCANF, or something similar simply will not work if you want all of the information. You will have to find an alternative approach, for example download BASE2BASE:

https://www.mathworks.com/matlabcentral/fileexchange/58850-base2base-nstart-bstart-bend

and use it like this:

a = '12362534624362643243256346523462';
b = base2base(a,10,2)

b = '10011100000010011000000011110110100110100000111111110111001000110111011110100110000110110011011101000110'

Answer 2

[KSSV]

a ='1234567'; 
dec2bin(str2num(a))

ans = '100101101011010000111'

[Ammy]

@KSSV Thank you, but there is a problem with more digits in a

like

a='12362534624362643243256346523462'

str2num(a)= 1.2363e+31

and then not giving the right output in binary form