# Bringing arrays to the same length

조회 수: 7(최근 30일)
Lev Mihailov 2022년 3월 2일
편집: Rik 2022년 3월 2일
There are three arrays (two vectors and a matrix), I need to bring them to the same length
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values ​​in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
% what do i need to get
ba=[ 1.2,1.3,1.4];
ma=[1,2;1,2;1,0];
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Benjamin Kraus 2022년 3월 2일
I'm having some trouble understanding your question.
If I understand correctly, you are trying to calculate the values in ba and ma based somehow on the values of a, b, and m, but I don't see how you calculate the values in ma from any of the vectors, and ba appears to be equal to a. Can you give more description (in words) of the algorithm you are hoping to use to derive ba and ma based on a, b, and m?

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### 답변(2개)

Rik 2022년 3월 2일
편집: Rik 2022년 3월 2일
There are two issues with the solution by Arif:
• It uses find on a logical array, but that is only used to index an array
• It assume the the first column in m will be 1 for all the rows we're looking for
The edits below solve both.
a=[ 1.2,1.3,1.4];
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[L,idx]=ismember(a,b); % find the element of a in b
ba=a(L)
ba = 1×3
1.2000 1.3000 1.4000
ma=m(idx(L),:)
ma = 3×2
1 2 1 2 1 0
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Arif Hoq 2022년 3월 2일
편집: Arif Hoq 2022년 3월 2일
try this:
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[idx]=find(ismember(b,a)); % find the element of a in b
ba=b(idx)
ba = 1×3
1.2000 1.3000 1.4000
ma=m((m==1),:) % find the first element=1
ma = 3×2
1 2 1 2 1 0

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