searching first two consecutive ones and set to 0

y=[1 1 1 1 1 1 1 1 1 1 1]

i want to search for first two consecutive ones everytime and allocate them 0

like this

y=[0 0 1 1 1 1 1 1 1 1 1]

Answer 1

[Arif Hoq]

try this:

y=[1 1 1 1 1 1 1 1 1 1 1];
idx=y(1:2);
b=find(y(idx));
if y(b)==1
    y(b)=0;
end
disp(y)

     0     0     1     1     1     1     1     1     1     1     1

[VASUNDHARA V]

Thankyou so much sir. i used find command incorrectly.tahnkyou once again

[Arif Hoq]

my pleasure

[Jan]

This does not work, if y does not start ith two 1 values:

y=[0 0 1 1 1 1 1 1 1 1 1]

y = 1×11

0 0 1 1 1 1 1 1 1 1 1

idx=y(1:2);
b=find(y(idx));

Array indices must be positive integers or logical values.

if y(b)==1
    y(b)=0;
end
disp(y)

Answer 2

[Jan]

y = [0 0 1 1 1 1 1 1 1 1 1];
index = strfind(y, [1, 1]);
if any(index)
   y(index(1):index(1)+1) = 0;
end
y

y = 1×11

0 0 0 0 1 1 1 1 1 1 1

[VASUNDHARA V]

thankyou @Jan sir , sir actually if it doesnot start with 1 like if it is 00011111 then i have not allowed to allocate in that case basically i have to block that path...but yes it blocks only when it first search so thankyou sir for this another case also.

[Jan]

As fas as I understand, this would be working then:

if all(y(1:2) == 1)

[VASUNDHARA V]

yes sir